At the zoo,the ratio of monkeys to gorillas is 5:1

Which equation can you use to solve for x? x + 56 = 180 x + 146 = 180 180−x=146 x + 56 = 146 The figure contains a pair intersec

Harlamova29_29 [7]

The correct question is
<span>Which equation can you use to solve for x? x + 56 = 180 x + 146 = 180 180−x=146 x + 56 = 146 The figure contains a pair intersecting lines. One of the four angles formed by the intersecting lines is labeled 146 degrees. The angle opposite and not adjacent to this angle is broken into two smaller angles by a ray that extends from the point where the two lines intersect. One of these smaller angles is labeled 56 degrees, and the other smaller angle is labeled x degrees.

see the picture attached to better understand the problem

we know that
angle 146</span>° and angle (56°+x°) area equal -----> by vertical angles
so
146=56+x
therefore

the answer is
<span>x + 56 = 146</span>

3 0

3 years ago

Can someone solve this

Natalka [10]

Option D:

ΔCAN ≅ ΔWNA by SAS congruence rule.

Solution:

Given data:

m∠CNA = m∠WAN and CN = WA

To prove that ΔCAN ≅ ΔWNA:

In ΔCAN and ΔWNA,

CN = WA (given side)

∠CNA = ∠WAN (given angle)

NA = NA (reflexive side)

Therefore, ΔCAN ≅ ΔWNA by SAS congruence rule.

Hence option D is the correct answer.

4 0

3 years ago

The perimeter of a triangular field is 120m. Two of the sides are 21m and 40m.Calculate the largest angle of the field.

Mama L [17]

Answer:

the largest angle of the field is 149⁰

Step-by-step explanation:

Given;

perimeter of the triangular filed, P = 120 m

length of two known sides, a and b = 21 m and 40 m respectively

The length of the third side is calculated as follows;

a + b + c = P

21 m + 40 m + c = 120 m

61 m + c = 120 m

c = 120 m - 61 m

c = 59 m

B

↓ ↓

A → → → → → → → → → → → C

Consider ABC as the triangular field;

Angle A is calculated by applying cosine rule;

$a^2 = b^2 + c^2 - 2bc \ Cos A\\\\Cos \ A = \frac{b^2 + c^2 - a^2}{2bc} \\\\Cos \ A = \frac{40^2 + 59^2 - 21^2}{2 \times 40 \times 59} \\\\Cos \ A = 0.983\\\\A = Cos ^{-1} (0.983)\\\\A = 10.6 \ ^0$

Angle B is calculated as follows;

$Cos \ B = \frac{a^2 + c^2 - b^2}{2ac} \\\\Cos \ B = \frac{21^2 + 59^2 - 40^2}{2 \times 21 \times 59} \\\\Cos \ B = 0.937\\\\B= Cos ^{-1} (0.937)\\\\B = 20.5 \ ^0$

Angle C is calculated as follows;

$Cos \ C = \frac{a^2 + b^2 - c^2}{2ab} \\\\Cos \ C = \frac{21^2 + 40^2 - 59^2}{2 \times 21 \times 40} \\\\Cos \ C = -0.857\\\\C = Cos ^{-1} (-0.857)\\\\C = 149\ ^0$

Therefore, the largest angle of the field is 149⁰.

8 0

3 years ago

Find the zeros of the function. Enter the solutions from least to greatest.

Harman [31]

9514 1404 393

Answer:

x = 5, x = 11

Step-by-step explanation:

Set f(x) = 0 and solve for x.

0 = (x -8)² -9

9 = (x -8)² . . . . . add 9

±√9 = x -8 . . . . . take the square root

±3 +8 = x . . . . . . . add 8

That is, ...

x = 8 -3 = 5 . . . . lesser x

x = 8 +3 = 11 . . . greater x

3 0

3 years ago

6 - 8x = 6x - 9x + 11

mars1129 [50]

6-8x=-3x+11

-8x+3x=11-6

-5x=5

x=-1

The first step is to isolate the variable, then you solve. Hope this helps, brainliest if you can.

6 0

3 years ago

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At the zoo,the ratio of monkeys to gorillas is 5:1​

At the zoo,the ratio of monkeys to gorillas is 5:1