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3 years ago

What is the tires weight in pounds?

Mathematics

1 answer:

poizon [28]3 years ago

5 0

Hey!

To solve this problem we must begin by writing out an equation.

Here's the equation I've created.

520 ÷ 453.592 = ?

Now we solve our created equation to get the answer.

520 ÷ 453.592 = 1.1464046985

That could be our final answer but sometimes you might want to round.

So, the tires weight in pounds is 1.1464046985 or 1.15.

Hope this helps!

- Lindsey Frazier ♥

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Three sphere of radius 4cm each fit inside a tube calculate the percentage of the tube.

bonufazy [111]

Answer:

66.6% (see below)

Step-by-step explanation:

Each sphere 4/3 $\pi$ r²=4/3 $\pi$ (4²)=268.08cm³

Assuming the tube is the same width and height as the three spheres,

V= $\pi$ r²h= $\pi$ (4²)24=1206.37

The three spheres are 268.08*3=804.24cm³

The tube is 1206.37cm³

I’m not sure if your question is asking the percentage of the tube that’s filled, or the percentage that’s unfilled.

Filled: 804.24÷1206.37=0.66666=66.6%

Unfilled: 1206.37-804.24=402.13

402.13÷106.37=0.33333=33.3%

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4 years ago

Зm — 5n = 11 what is this answer?

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3 years ago

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Is anyone good with Trigonometry word problems?

muminat

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Step-by-step explanation:

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3 years ago

For positive acute angles A and B, it is known that cos A= 20/29 and tan B= 11/60. Find the value of cos(A + B) in simplest form

jek_recluse [69]

Answer:

$\displaystyle \cos(A + B) =\frac{969}{1769}$

Step-by-step explanation:

We are given that:

$\displaystyle \cos A=\frac{20}{29}\text{ and } \tan B=\frac{11}{60}$

Where A and B are positive acute angles.

And we want to find cos(A + B).

Recall that cosine is the ratio of the adjacent side to the hypotenuse. Using this information, find the opposite side with respect to Angle A:

$o=\sqrt{29^2-20^2}=21$

Tangent is the ratio of the opposite side to the adjacent side. Find the hypotenuse with respect to Angle B:

$h=\sqrt{11^2+60^2}=61$

In summary:

With respect to Angle A, the adjacent side is 20, opposite is 21, and the hypotenuse is 29.

With respect to Angle B, the adjacent side is 60, the opposite is 11, and the hypotenuse is 61.

We can rewrite our expression as:

$\displaystyle \cos(A+B)=\cos A\cos B-\sin A\sin B$

Using the above information, substitute in the appropriate values. Note that since A and B are positive acute angles, all trigonometric values will be positive. Hence:

$\displaystyle \cos(A + B)=\left(\frac{20}{29}\right)\left(\frac{60}{61}\right)-\left(\frac{21}{29}\right)\left(\frac{11}{61}\right)$

Simplify:

$\displaystyle \cos(A + B) =\frac{1200-231}{1769}=\frac{969}{1769}$

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3 years ago