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Vikentia [17]
3 years ago
10

Subtract the polynomials.

Mathematics
1 answer:
ANTONII [103]3 years ago
8 0
(3x^{2} + 5x + 7) - (-4x^{2} + 3x - 6)

3x^{2} + 5x + 7 + 4x^{2} - 3x + 6

7x^2 + 2x + 13

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\bf \text { Answer :} 7x^2 + 2x + 13 \text {( Answer C)}
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Find the amount of the annuity due. Round to the nearest cent.
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FVAD=158917.84
6 0
3 years ago
30 is what percent of 200?​
madam [21]

Answer:

15 percent

Step-by-step explanation:

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5 0
3 years ago
According to an article in Newsweek, the rate of water pollution in China is more than twice that measured in the US and more th
jeyben [28]

Answer:

(a) 0.119

(b) 0.1699

Solution:

As per the question:

Mean of the emission, \mu = 11.7 million ponds/day

Standard deviation, \sigma = 2.8 million ponds/day

Now,

(a) The probability for the water pollution to be at least 15 million pounds/day:

P(X\geq 15) = P(\frac{X - /mu}{\sigma} \geq \frac{15 - 11.7}{2.8})

P(X\geq 15) = P(Z \geq 1.178)

P(X\geq 15) = 1 - P(Z < 1.178)

Using the Z score table:

P(X\geq 15) = 1 - 0.881 = 0.119

The required probability is 0.119

(b) The probability when the water pollution is in between 6.2 and 9.3 million pounds/day:

P(6.2 < X < 9.3) = P(\frac{6.2 - 11.7}{2.8} < \frac{X - \mu}{\sigma} < \frac{9.3 - 11.7}{2.8})

P(6.2 < X < 9.3) = P(- 1.96 < Z < - 0.86)

P(6.2 < X < 9.3) = P(- 1.96 < Z < - 0.86)

P(Z < - 0.86) - P(Z < - 1.96)

Now, using teh Z score table:

0.1949 - 0.025 = 0.1699

4 0
3 years ago
Please help ASAP 15 POINTS BRAINIEST ANSWER!!
maxonik [38]
1) around 1300

2) around 30

3) a. about 500
    b. about 2600

Hope this helps you!
7 0
4 years ago
Which lines must be parallel?
Gnom [1K]

Answer:

The answer is option A) <em>r</em><em> </em>and <em>s</em>

3 0
3 years ago
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