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3 years ago

When estimating you should use what numbers Odd Even Large Round

Mathematics

1 answer:

Tanya [424]3 years ago

4 0

Answer:

Round

Step-by-step explanation:

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I need help please... im really confused

NeTakaya

when we divides m(x) ÷n(x) quotient and remainder is

6 0

3 years ago

If S_1=1,S_2=8 and S_n=S_n-1+2S_n-2 whenever n≥2. Show that S_n=3⋅2n−1+2(−1)n for all n≥1.

Snezhnost [94]

You can try to show this by induction:

• According to the given closed form, we have $S_1=3\times2^{1-1}+2(-1)^1=3-2=1$ , which agrees with the initial value S₁ = 1.

• Assume the closed form is correct for all n up to n = k. In particular, we assume

$S_{k-1}=3\times2^{(k-1)-1}+2(-1)^{k-1}=3\times2^{k-2}+2(-1)^{k-1}$

and

$S_k=3\times2^{k-1}+2(-1)^k$

We want to then use this assumption to show the closed form is correct for n = k + 1, or

$S_{k+1}=3\times2^{(k+1)-1}+2(-1)^{k+1}=3\times2^k+2(-1)^{k+1}$

From the given recurrence, we know

$S_{k+1}=S_k+2S_{k-1}$

so that

$S_{k+1}=3\times2^{k-1}+2(-1)^k + 2\left(3\times2^{k-2}+2(-1)^{k-1}\right)$

$S_{k+1}=3\times2^{k-1}+2(-1)^k + 3\times2^{k-1}+4(-1)^{k-1}$

$S_{k+1}=2\times3\times2^{k-1}+(-1)^k\left(2+4(-1)^{-1}\right)$

$S_{k+1}=3\times2^k-2(-1)^k$

$S_{k+1}=3\times2^k+2(-1)(-1)^k$

$\boxed{S_{k+1}=3\times2^k+2(-1)^{k+1}}$

which is what we needed. QED

6 0

3 years ago

What is the multiplicative inverse of (-3) + (-6) quick place

Yuri [45]

Answer:

-1/6

Step-by-step explanation:

I looked it up

8 0

2 years ago

Enter the equation of the circle described below. Center (-1,4), radius = sqrt3

slava [35]

The equation of a circle always follows this:

(x - x1) + (y - y1) = r^2

x1 and y1 represent the coordinates as POSITIVE numbers and the r represent the radius

Your answer is (x + 1) + (y - 4) = 3

8 0

3 years ago

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Anna35 [415]

Answer:

tha

Step-by-step explanation:

4 0

3 years ago