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3 years ago

Hhhhhhhhhhhhheeeeeeellllllllppppppppp

Mathematics

1 answer:

n200080 [17]3 years ago

7 0

Answer:

With whattttttttttttttttttttttttttt

Step-by-step explanation:

You might be interested in

Write the equation in slope-intercept form in each line based on the information give

olchik [2.2K]

Answer:

y= 6x -8

Step-by-step explanation:

Slope-intercept form:

y= mx +c, where m is the gradient and c is the y-intercept.

$\boxed{gradient = \frac{y1 - y2}{x1- x2} }$

Gradient

$= \frac{4 - ( - 2)}{2 - 1}$

= 6

y= 6x +c

To find the value of c, substitute the equation with a pair of coordinates.

When x= 1, y= -2,

-2= 6(1) +c

c= -2 -6 (-6 on both sides)

c= -8

Thus, the equation of the line is y= 6x -8.

8 0

3 years ago

Which option shows the graph of 4y + 8<-3x?

Makovka662 [10]

Look at my upload to see the graph, I couldn't see the choices, so I can't give you a definite answer. But the graph below is the correct one.

Hope that helped!

8 0

2 years ago

The total length of three boards is 7/8 of a yard. The length of two of the boards are 1/4 of a yard and 3/16 of a yard. What is

grigory [225]

Answer:

7/16 of a yard

Step-by-step explanation:

Let's put the boards to the same denominator so it's easier.

Let's go with a denominator of 16

1/4= 4/16

7/8= 14/16

3/16 stays the same.

So, 4/16+3/16+x=14/16

7/16+x=14/16

x=7/16 of a yard, the length of the 3rd board.

6 0

3 years ago

In a shipment of 56 vials, only 13 do not have hairline cracks. If you randomly select 3 vials from the shipment, in how many wa

Elden [556K]

Answer: 27434

Step-by-step explanation:

Given : Total number of vials = 56

Number of vials that do not have hairline cracks = 13

Then, Number of vials that have hairline cracks =56-13=43

Since , order of selection is not mattering here , so we combinations to find the number of ways.

The number of combinations of m thing r things at a time is given by :-

$^nC_r=\dfrac{n!}{r!(n-r)!}$

Now, the number of ways to select at least one out of 3 vials have a hairline crack will be :-

$^{13}C_2\cdot ^{43}C_{1}+^{13}C_{1}\cdot ^{43}C_{2}+^{13}C_0\cdot ^{43}C_{3}\\\\=\dfrac{13!}{2!(13-2)!}\cdot\dfrac{43!}{1!(42)!}+\dfrac{13!}{1!(12)!}\cdot\dfrac{43!}{2!(41)!}+\dfrac{13!}{0!(13)!}\cdot\dfrac{43!}{3!(40)!}\\\\=\dfrac{13\times12\times11!}{2\times11!}\cdot (43)+(13)\cdot\dfrac{43\times42\times41!}{2\times41!}+(1)\dfrac{43\times42\times41\times40!}{6\times40!}\\\\=3354+11739+12341=27434$