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vladimir1956 [14]

3 years ago

15

Convert an annual rate of 0.224% to a generation rate (20 years)

1 answer:

Sedaia [141]3 years ago

4 0

2.78 that will be the awnser if you go gor it

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9966 [12]

Answer:

it's C

Step-by-step explanation:

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3 years ago

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|3k-2|=2|k+2| solve please

djyliett [7]

3k-2=2k+4
-2k. -2k
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4 0

3 years ago

A compound inequality is graphed and its graph consists of all real numbers. Which of the following could have resulted in this

Feliz [49]

"r < 3 or r > 2" is the one among the following choices given in the question that <span>could have resulted in this solution set. The correct option among all the options that are given in the question is the fourth option or option "d". I hope that this is the answer that has actually come to your desired help.</span>

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3 years ago

A particle moves on the hyperbola xy=18 for time t≥0 seconds. At a certain instant, y=6 and dydt=8. What is x that this instant?

professor190 [17]

Answer:

The value of x at this instant is 3.

Step-by-step explanation:

Let $x\cdot y = 18$ , we get an additional equation by implicit differentiation:

$x\cdot \frac{dy}{dt}+y\cdot \frac{dx}{dt} = 0$ (1)

From the first equation we find that:

$x = \frac{18}{y}$ (2)

By applying (2) in (1), we get the resulting expression:

$\frac{18}{y}\cdot \frac{dy}{dt}+y\cdot \frac{dx}{dt} = 0$ (3)

$y\cdot \frac{dx}{dt}=-\frac{18}{y}\cdot \frac{dy}{dt}$

$\frac{dx}{dt} = -\frac{18}{y^{2}} \cdot \frac{dy}{dt}$

If we know that $y = 6$ and $\frac{dy}{dt} = 8$ , then the first derivative of x in time is:

$\frac{dx}{dt} = -\frac{18}{6^{2}} \cdot (8)$

$\frac{dx}{dt} = -4$

From (1) we determine the value of x at this instant:

$x\cdot \frac{dy}{dt} = -y\cdot \frac{dx}{dt}$

$x = -y\cdot \left(\frac{\frac{dx}{dt} }{\frac{dy}{dt} } \right)$

$x = -6\cdot \left(\frac{-4}{8} \right)$

$x = 3$

The value of x at this instant is 3.

4 0

3 years ago

What is the mean in these numbers 50 60 80 90 100

Korolek [52]

Answer:

76

Step-by-step explanation:

<h2>MARK ME BRAINLIEST PLZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZ</h2>

8 0

3 years ago

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