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fredd [130]
3 years ago
15

Consider the expression √(√625).

Mathematics
1 answer:
const2013 [10]3 years ago
6 0

Answer:

5

Step-by-step explanation:

Square Root - Finding a number that multiplies itself twice into the number within the square root

With this meaning, we need to find a number that multiplies itself into 625.

Finding calculations using exponents will help,

25^2 is equal to 625. Therefore \sqrt{25}

We are not finished, as there is another square root right after, empowering the parenthesis, so what number multiplies itself equals 25?

This would be 5, therefore \sqrt{(\sqrt{625}) } is equal to 5.

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Answer:

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3 years ago
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Use a 30degrees and -60degrees right triangle to find the exact value of the following trigonometric expression. Cot 30 degrees=
LuckyWell [14K]

The dirty little secret about trig is students mostly just need to understand the 45/45/90 right isosceles triangle and the 30/60/90 triangle, which is half an isosceles triangle.  

I'm sure you have seen it many times already, so I'll remind you in the 30/60/90 right triangle the sides opposite those angles are respectively in the ratio 1: \sqrt{3}:2.  Remember the smallest side is always opposite the smallest angle, etc.   These make a right triangle because

1^2 + \sqrt{3}^2 = 2^2

So in this hypotenuse 2 triangle, the length 1 side is opposite the 30 degree angle and the \sqrt{3} side is adjacent to it.

We could jump right to the answer but let's enumerate all the trig functions.  Really you should memorize the sine and cosine so you can get these quickly.

\cos 30^\circ = \dfrac{ \textrm{adjacent} }{ \textrm{hypotenuse} } = \dfrac{\sqrt{3}}{2}

\sin 30^\circ = \dfrac{ \textrm{opposite} }{ \textrm{hypotenuse} } = \dfrac{1}{2}

\tan 30^\circ = \dfrac{ \textrm{opposite} }{ \textrm{adjacent} }= \dfrac{1}{\sqrt{3}} =\dfrac{\sqrt{3}}{3}

\cot 30^\circ = \dfrac{ \textrm{adjacent} }{ \textrm{opposite}} = \dfrac{\sqrt{3}}{1} =\sqrt{3}

\sec 30^\circ = \dfrac{ \textrm{hypotenuse} }{ \textrm{adjacent}}= \dfrac{2}{\sqrt{3}}

\csc 30^\circ = \dfrac{ \textrm{hypotenuse} }{ \textrm{opposite}}= \dfrac{2}{1} = 2

We want the cotangent, another way to get it is

\cot 30^\circ = \dfrac{\cos 30^\circ}{\sin 30^\circ} = \dfrac{\sqrt{3}/2}{1/2} = \sqrt{3}

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3 years ago
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Alexandra [31]

Answer:

D

Step-by-step explanation:

There are 1.61 km in 1 mi.

10 mi × (1.61 km/mi) = 16.1 km

7 0
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In the following equation, f(x)=2x +7, what is f(-3)?
Helen [10]

Answer:

f(-3) = 1

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

<u>Algebra I</u>

  • Function Notation

Step-by-step explanation:

<u>Step 1: Define</u>

f(x) = 2x + 7

f(-3) is x = -3

<u>Step 2: Evaluate</u>

  1. Substitute:                   f(-3) = 2(-3) + 7
  2. Multiply:                       f(-3) = -6 + 7
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Write the following using algebraic notation, using the letter x for any
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You do X2 + 15 and that will be your answer.

By the way, the 2 is a power and is meant to be smaller on top of the X.

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