In a monohybrid cross, if the gene for tall (T) plants was incompletely dominant over the gene for short (t) plants, what would
be the predicted result of crossing two intermediate (Tt) parent plants? (Hint: You may want to complete a Punnett square.) 25 percent tall, 50 percent intermediate, 25 percent short
50 percent tall, 25 percent intermediate, 25 percent short
100 percent intermediate 25 percent tall, 75 percent intermediate
Incomplete dominance is when the dominant allele is not fully dominant over the recessive allele. This results in three phenotype options rather than three. in this case T= tall, t= short and the two combined would be an intermediate height. A punnet square can help you figure this out. T t T TT Tt t Tt tt
In this case you have one genotype that is two tall (TT) alleles. This will present as a tall plant. The second genotype present is two short alleles (tt). You have one of these that will result in a short plant. The third genotype present is one of each (Tt). This will result in an intermediate height plant. This shows up twice in the punnet square. Based on this you will have 25% tall, 25% short and 50% intermediate.
The nurse should approach the client in a calm way and to
explain the greenish amniotic fluid to prevent the woman from being stressed
out or to cause an outbreak, the nurse should explain that the greenish
amniotic fluid was mostly likely because of a presence of late decelerations in
which is indicative of a presence of fetal distress. It is likely because there
is a presence of blood flow that is poor or the fetus is has been experiencing
poor nourishment or oxygen in which it needs to survive in the mother’s womb
and the green fluid was also because of the meconium.
