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3 years ago

The sum of the angle measures of a quadrilateral is 360° Write and 85 115 60

Mathematics

1 answer:

Misha Larkins [42]3 years ago

3 0

The third angle would be 100 degrees
Explanation: 360-85-115-60= 100

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Please help! I need the surface area for both. Absurd answer are not tolerated. Thanks if you help!

Natasha_Volkova [10]

Answer:

<h3>Figure 1</h3>

Perimeter of base = 5 + 5 + 8 = 18 ft

Height = 7 ft

Base area = 1/2(8)(3) = 12 ft²

<u>Surface area:</u>

S = 18*7 + 2*12 = 150 ft²

<h3>Figure 2</h3>

<u>Surface area of cube:</u>

S = 6a² = 6(2.5)² = 37.5 m²

<u>Surface area of prism:</u>

S = 2(11 + 9)(7) = 280 m²

<u>Overlapping area:</u>

S = 2.5² = 6.25 m²

<u>Surface area of composite figure:</u>

S = 280 + 37.5 - 2(6.25) = 305 m²

4 0

3 years ago

52% of ______ days is 13 days.

abruzzese [7]

'of' in mathematics means multiplication
'is' in mathematics means equal

52% * x = 13

52/100 * x = 13

0.52x = 13

x = 13/0.52

x = 25

52% of 25 days is 13 days.

8 0

3 years ago

Changethe improper fraction into an equal mixed number 15/4

frez [133]

Answer:

15 divided by 4 = 3 3/4

Step-by-step explanation:

First divide 15 on 4 to get 3.75. convert 3.75 to a fraction. 3 will stay as three, and 0.75 will be converted to 3/4. the answer to your question is 3 and 3/4. I hope this was correct. if it was then please mark as brainliest.

3 0

3 years ago

Read 2 more answers

Use the quadratic formula to solve the following equation -3x^2-x-3=0

tigry1 [53]

<u>Answer:</u>

$x=-\frac{1}{6}-\frac{\sqrt{35}}{6} i \text { and } x=-\frac{1}{6}+\frac{\sqrt{35}}{6} i$ are two roots of equation $-3 x^{2}-x-3=0$

<u>Solution:</u>

Need to solve given equation using quadratic formula.

$-3 x^{2}-x-3=0$

General form of quadratic equation is $a x^{2}+b x+c=0$

And quadratic formula for getting roots of quadratic equation is

$x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}$

In our case b = -1 , a = -3 and c = -3

Calculating roots of the equation we get

$\begin{array}{l}{x=\frac{-(-1) \pm \sqrt{(-1)^{2}-4(-3)(-3)}}{2 \times-3}} \\\\ {x=-\frac{1}{6} \pm\left(-\frac{\sqrt{-35}}{6}\right)}\end{array}$

Since $b^{2}-4 a c$ is equal to -35, which is less than zero, so given equation will not have real roots and have complex roots.

$\begin{array}{l}{\text { Hence } x=-\frac{1}{6}-\frac{\sqrt{35}}{6} i \text { and } x=-\frac{1}{6}+\frac{\sqrt{35}}{6} i \text { are two roots of equation - }} \\ {3 x^{2}-x-3=0}\end{array}$

8 0

3 years ago

NEED HELP ASAP!!

rosijanka [135]

The boats would be 7.62 mi apart

5 0

2 years ago

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