You reverse what you did, so first you go 5 units down which makes the coordinates (9,1) then you move 3 units left which then is (6,1). Then you go 4 units up which lets you end out at (6,5).
Answer:
36
Step-by-step explanation:
All you gotta do is 9x4 or 9+9+9+9=36
The second matrix ![\left[\begin{array}{ccc}-6&3&12\\0&15&-24\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-6%263%2612%5C%5C0%2615%26-24%5Cend%7Barray%7D%5Cright%5D)
represents the triangle dilated by a scale factor of 3.
Step-by-step explanation:
Step 1:
To calculate the scale factor for any dilation, we divide the coordinates after dilation by the same coordinated before dilation.
The coordinates of a vertice are represented in the column of the matrix. Since there are three vertices, there are 2 rows with 3 columns. The order of the matrices is 2 × 3.
Step 2:
If we form a matrix with the vertices (-2,0), (1,5), and (4,-8), we get
![\left[\begin{array}{ccc}-2&1&4\\0&5&-8\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-2%261%264%5C%5C0%265%26-8%5Cend%7Barray%7D%5Cright%5D)
The scale factor is 3, so if we multiply the above matrix with 3 throughout, we will get the matrix that represents the vertices of the triangle after dilation.
Step 3:
The matrix that represents the triangle after dilation is given by
![3\left[\begin{array}{ccc}-2&1&4\\0&5&-8\end{array}\right] = \left[\begin{array}{ccc}3(-2)&3(1)&3(4)\\3(0)&3(5)&3(-8)\end{array}\right] = \left[\begin{array}{ccc}-6&3&12\\0&15&-24\end{array}\right]](https://tex.z-dn.net/?f=3%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-2%261%264%5C%5C0%265%26-8%5Cend%7Barray%7D%5Cright%5D%20%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D3%28-2%29%263%281%29%263%284%29%5C%5C3%280%29%263%285%29%263%28-8%29%5Cend%7Barray%7D%5Cright%5D%20%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-6%263%2612%5C%5C0%2615%26-24%5Cend%7Barray%7D%5Cright%5D)
This is the second option.
Answer:
B) Adjacent
Step-by-step explanation:
The hypotenuse will ALWAYS be designated as the longest side in a right triangle.
Pretend that the angle (the one with the round line) is an eyeball that is looking outwards. The eye is looking out at side BC. That means that line BC is opposite of the angle.
This leaves one side left: the adjacent side. The adjacent side is the side next to the angle. But it is the side that is NOT the hypotenuse.
Given that Amistad deposited $2,163.27 in a savings account that earns 3.9% simple interest.
That means we need to use Simple interest formula to find the Amistad's account balance in nine months.
Simple interest formula is
A=P(1+RT)
Where P= principal amount = $2163.27
R= rate of interest = 3.9%= 0.039
T= time in years = 9 months = 9/12 years = 0.75
Now plug these values into above formula:
A=2163.27(1+0.039* 0.75)
A=2163.27(1+0.02925)
A=2163.27(1.02925)
A=2226.5456475
Hence Amistad's account balance in nine months will be approx $2226.55
