Answer:
1/3
Step-by-step explanation:
To change from one base to another, we use the formula
Logb x = Loga x/Loga b
log1/9 (3^(1/3) /3)
log3 ((3^(1/3) /3))
-------------------------
log3 (1/9)
Log a /b = log a - log b
and 1/9 = 3^-2
log3 ((3^(1/3) ) - log3 (3)
-------------------------
log3 (3^-2)
log a^b = blog a
1/3 log3 (3 ) - log3 (3)
-------------------------
-2log3 (3)
We know log3 (3) =1
1/3 (1) - 1
-------------------------
-2 (1)
1/3 - 1
-------------------------
-2
-2/3
------
-2
Copy dot flip
-2/3 * -1/2
1/3
For matrix subtraction, you subtract the corresponding cell of the second matrix from the first. So, looking at the first spot, you have 4 (from the first matrix) - 4 (from the second matrix) = 0 (the first number in the output matrix). Continuing that for the next spot, -4 - -3 = -4 + 3 = -1. Finally, -2 - 5 = -7. This means your answer is [0 -1 -7].
The correct answer is a= -2
Answer:
5, 17
Step-by-step explanation:
For this problem, you need to create a system of equations.
We can name one number x and the other y.
First equation: 2x + 7 = y
Second equation: x + y - 10 = 12, or x + y = 22.
We know y = 2x + 7, so we can substitute that into the second equation.
x + 2x + 7 = 22.
3x = 15
x = 5.
Plug x back into the first equation:
2 · 5 + 7 = y.
y = 10 + 7
y = 17.
4/8+1/16= > (4*2)/8+1/16=>(8+1)/16=> 9/16
