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3 years ago

13

Simplify show your work

1 answer:

Alexandra [31]3 years ago

5 0

Simplify the first fraction:
$\frac{3n^{2}-n}{n^{2}-1} = \frac{3n(n-1)}{(n+1)(n-1)} = \frac{3n}{n+1}$

Your equation becomes:
$\frac{3n}{n+1} + \frac{n^{2} }{n+1} \\ = \frac{n^{2} + 3n}{n+1} \\ = \frac{n(n + 3)}{n+1}$

That last fraction becomes your final answer.

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zhuklara [117]

Answer:

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Step-by-step explanation:

<em>Lets explain how to find the measure of an angle from the length of the </em>

<em>sides of the triangle</em>

- We can do that by using the cosine rule

- If the three angles of the triangle are A , B , C, then the side opposite

to angle A is BC , the side opposite to angle B is AC and the side

opposite to angle C is AB, So to find measure of angle A use the rule

$cos(A)=\frac{(AB)^{2}+(AC)^{2}-(BC)^{2}}{2(AB)(AC)}$

<em>Lets solve the problem</em>

- Assume that the triangle is ABC where AB = 14 cm , BC = 10 cm and

AC = 6 cm

- We need to find the measure of the largest angle

- The largest angle is opposite to the longest side

∵ The longest side is AB

∴ The largest angle is C

By using the rule above

∴ $cos(C)=\frac{(AC)^{2}+(BC)^{2}-(AB)^{2}}{2(AC)(BC)}$

∵ AB = 14 cm , BC = 10 cm , AC = 6 cm

∴ $cos(C)=\frac{(6)^{2}+(10)^{2}-(14)^{2}}{2(6)(10)}$

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