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3 years ago

7

Jason bought 7 new baseball trading cards to add to his collection. The next day his dog ate half of his collection. There are n

ow only 30 cards left. How many cards did he start with?

2 answers:

swat323 years ago

8 0

Answer:

53

Step-by-step explanation:

53+7=60-half=30

Stels [109]3 years ago

5 0

Answer:

geegegtkfifigjfjrjicirjjfigjrkivigk

Step-by-step explanation:

bgfeefcfifirifiridurjfjdjdjdjdj

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An electrician charges Mr. Speer $300 before sales tax, for wiring his home. (a) What is the amount of sales tax that Mr. Speer

PilotLPTM [1.2K]

Answer: See explanation

Step-by-step explanation:

Your question isn't complete as you didn't give the sales tax percent. In order to solve the question, let's assume that the sales tax is 6%.

(a) What is the amount of sales tax that Mr. Speer has to pay?

This will be:

= Sales tax percent × Amount charged

= 6% × $300

= 6/100 × $300

= 0.06 × $300

= $18

The sale tax is $18

(b) What is the total amount Mr. Speer has to pay?.

The total amount will be the addition of the amount charged and the sales tax. This will be:

= $300 + $18

= $318

4 0

2 years ago

A certain unsavory bar for poker-playing dogs is attended by only two types of dogs: "good dogs" and "bad dogs." For a randomly

SVETLANKA909090 [29]

Answer: The required probability is 0.1923.

Step-by-step explanation:

Since we have given that

Probability that it's a good dog = 0.4

Probability that it's a bad dog = 1-0.4 = 0.6

Probability that the dog smokes given that its a bad dog = 0.7

Probability that it smokes given that its a good dog = 0.25

According to question, probability of smoking pipe would be

P(good).P(Smoking pipe|good)+P(bad).P(smoking pipe|bad)

$0.4\times 0.25+0.6\times 0.7\\\\=0.1+0.42\\\\=0.52$

So, Probability of getting a good dog given that it is smoking pipe is given by

$\dfrac{P(good).P(smoking\ pipe|good)}{P(smoking\ pipe)}\\\\=\dfrac{0.4\times 0.25}{0.52}\\\\=\dfrac{0.1}{0.52}\\\\=0.1923$

Hence, the required probability is 0.1923.

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2 years ago

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The price of an article with 13% VAT is Rs. 2,034. What is

Jobisdone [24]

Step-by-step explanation:

this will may be helpful for you.

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2 years ago

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What’s the answer??? (SOMEONE PLEASE HELP)

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$\frac{ - 24 {x}^{4}{y}^{3} }{8 {x}^{6} {y}^{2} } = \frac{ - 3y}{ {x}^{2} }$

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3 years ago

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A trough of water is 20 meters in length and its ends are in the shape of an isosceles triangle whose width is 7 meters and heig

Vaselesa [24]

Answer:

a) Depth changing rate of change is $0.24m/min$ , When the water is 6 meters deep

b) The width of the top of the water is changing at a rate of $0.17m/min$ , When the water is 6 meters deep

Step-by-step explanation:

As we can see in the attachment part II, there are similar triangles, so we have the following relation between them $\frac{3.5}{10} =\frac{a}{h}$ , then $a=0.35h$ .

a) As we have that volume is $V=\frac{1}{2} 2ahL=ahL$ , then $V=(0.35h^{2})L$ , so we can derivate it $\frac{dV}{dt}=2(0.35h)L\frac{dh}{dt}$ due to the chain rule, then we clean this expression for $\frac{dh}{dt}=\frac{1}{0.7hL}\frac{dV}{dt}$ and compute with the knowns $\frac{dh}{dt}=\frac{1}{0.7(6m)(20m)}2m^{3}/min=0.24m/min$ , is the depth changing rate of change when the water is 6 meters deep.

b) As the width of the top is $2a=0.7h$ , we can derivate it and obtain $\frac{da}{dt}=0.7\frac{dh}{dt} =0.7*0.24m/min=0.17m/min$ The width of the top of the water is changing, When the water is 6 meters deep at this rate

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2 years ago