The height of a soccer ball can be modeled by the function h(t) = - 8t2 + 32t. Where h(t) is the height in feet and t is the in
seconds. Find the time when the soccer ball reaches its maximum height
1 sec
2 sec
3 sec
4 sec
1 answer:
Answer:
2 seconds
Step-by-step explanation:
We want to find when h(t) =0
0 = - 8t^2 + 32t
factor out a -8t
0 = -8t( t-4)
Using the zero product property
-8t = 0 and t-4=0
t = 0 and t=4
t=0 is when it is dropped and t=4 is when it lands
The maximum height is halfway in between
(0+4) /2
2 seconds
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