Find the difference 6 - 3 2/5
2 answers:
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Answer:
Step-by-step explanation:
Given that a cheese can be classified as either raw dash milk or pasteurized. Suppose that 91% of cheeses are classified as pasteurized.
Each cheese is independent of the other and there are only two outcomes.
Hence X = no of cheeses pasteurized is binomial (2,0.91)
a) P(x=2 ) when n=2 is
b) n=6.
P(x=6) =
c) P(atleast one raw dash milk) = 1-P(all pasteurised)
=0.8281
Since probability is 0.83 it is not unusual.