3 years ago

Hi can someone help me by explaining how to do inverse operations? I need the operations for base and lenght

Mathematics

1 answer:

taurus [48]3 years ago

7 0

Answer:

inverse operations (KristaKingMath)

You might be interested in

Given the following triangle solve for the unknown angle.

svetlana [45]

Since it is shown that 2 of the sides of the triangle are congruent, we can assume that they have the same angle measures.

so to solve for the missing angle you can set up an equation equal to 180 since all triangles add up to 180 degrees.
21 + 21 + x = 180
42 + x = 180
x = 138

the value of the missing angle should be 138 degrees

hope this helped

4 0

3 years ago

Write a polynomial function that has the zeros -3, 1, -1 and has a leading coefficient of 1.

maks197457 [2]

Answer:

x3+3x2-x-3

Step-by-step explanation:

4 0

2 years ago

1.8+3.5y+0.9+9=16.2<br> plz help

saul85 [17]

Answer:

The Awnser Is Y=9/7

Step-by-step explanation:

7 0

3 years ago

8^(3x-1)=2^8 <br><br>Solve for x

Yuri [45]

$8^{(3x-1)}=2^8 \\\\ 2^{3(3x-1)}=2^8 \\\\ 3(3x-1)=8 \\\\ 9x-3=8 \\\\ 9x=8+3 \\\\ 9x=11 \\\\ \boxed{x=\frac{11}{9}}$

4 0

3 years ago

Read 2 more answers

2x(squared) + 23x-19=0

Helen [10]

Use quadratic formula

for ax^2+bx+c=0
x= $\frac{-b+/- \sqrt{b^2-4ac} }{2a}$

given
2x^2+23x-19=0
a=2
b=23
c=-19

x= $\frac{-23+/- \sqrt{23^2-4(2)(-19)} }{2(2)}$
x= $\frac{-23+/- \sqrt{529-152} }{4}$
x= $\frac{-23+/- \sqrt{377} }{4}$

x= $\frac{-23+ \sqrt{377} }{4}$ or $\frac{-23- \sqrt{377} }{4}$

7 0

3 years ago