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storchak [24]
3 years ago
5

Suppose the parent population has an exponential distribution with a mean of 15 and standard deviation of 12. Use the Central Li

mit Theorem to describe the distribution of when drawing samples of size 30.
Mathematics
1 answer:
bazaltina [42]3 years ago
4 0

Answer:

The sampling distribution of the sample mean of size 30 will be approximately normal with mean 15 and standard deviation 2.19.

Step-by-step explanation:

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

For the population, we have that:

Mean = 15

Standard deviaiton = 12

Sample of 30

By the Central Limit Theorem

Mean 15

Standard deviation s = \frac{12}{\sqrt{30}} = 2.19

Approximately normal

The sampling distribution of the sample mean of size 30 will be approximately normal with mean 15 and standard deviation 2.19.

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