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3 years ago

10

What is the solution for the system of equations? -4x+y=-2 y+5=-6x

1 answer:

Aliun [14]3 years ago

6 0

Answer:

(-3/10,-16/5)

Step-by-step explanation:

One way to solve a system of equations is by elimination. We can take one equation and subtract the other equation from it to cancel out on of the variables making the equation into something we can solve. In this case the Y's will cancel out because we have 1 Y in each equation

-4x+y=-2

6x+y=-5 subtract

-4x-6x=-10x

y-y=0

-2-(-5)=3

so our equation is -10x=3 and we can solve for x giving us x=-3/10

now we can plug -3/10 in for x into either of the original equations and solve for Y

y+5=-6(-3/10)

y+5=9/5

y=-16/5

so our answer is (-3/10,-16/5)

I hope this helps and please don't hesitate to ask if there is anything still unclear!

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Which expression is equivalent to (4g3h2k4)3

RSB [31]

Answer:

d) $8g^{6}h^{4} k^{12} - (h^{25} k^{15} )$

$\frac{(4g^{3} h^{2}k^{4} )^{3} }{8g^{3}h^{2} } - (h^{5} k^{3} )^{5}$ $= 8g^{6}h^{4} k^{12} - (h^{25} k^{15} )$

Step-by-step explanation:

<u><em>Explanation</em></u>

Given expression

= $\frac{(4g^{3} h^{2}k^{4} )^{3} }{8g^{3}h^{2} } - (h^{5} k^{3} )^{5}$

By using

(ab)ⁿ = aⁿbⁿ

$\frac{a^{m} }{a^{n} } = a^{m-n}$

= $\frac{(4)^{3} g^{9} h^{6}k^{12} ) }{8g^{3}h^{2} } - (h^{5} k^{3} )^{5}$

After simplification , we get

$= 8g^{9}g^{-3} h^{6} h^{-2} k^{12} - (h^{5} k^{3} )^{5}$

$= 8g^{9-3}h^{6-2} k^{12} - (h^{5} k^{3} )^{5}$

$= 8g^{6}h^{4} k^{12} - (h^{25} k^{15} )$

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2 years ago

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BARSIC [14]

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2 years ago

What value of n makes this expression equal to 6?<br><br> 3n - (2 + n)

SVEN [57.7K]

Answer:

4

Step-by-step explanation:

3n-2-n=6

2n-2=6

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5 0

3 years ago

Read 2 more answers

Is this correct???

GaryK [48]

Answer:

There's supposed to be nothing in the 7 and 8 columns

Step-by-step explanation:

You were good, but there aren't any in the 7 or 8 columns, making 9 an outlier.

hope this helps:)

5 0

3 years ago