3 years ago

Find the value of cos x if the value of sin x=3/5 and x is acute angle

1 answer:

3 0

Sin = opposite / hypotenuse
cos = adjacent / hypotenuse

using pythagoras theorem =

adjacent = 5^2-3^2
= 16
= square root 16
=4

cos x = 4/5

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Damm [24]

Answer:

The coordinates of the intersection of the medians of △ABC is (1/3, 1).

Step-by-step explanation:

Consider the vertices of △ABC are A(2, 4), B(−4, 0), and C(3, −1).

Intersection of the medians of a triangle is known as centroid.

Formula for centroid of a triangle is

$Centroid=(\dfrac{x_1+x_2+x_3}{3},\dfrac{y_1+y_2+y_3}{3})$

Using the above formula the centroid of △ABC is

$Centroid=(\dfrac{2-4+3}{3},\dfrac{4+0-1}{3})$

$Centroid=(\dfrac{1}{3},\dfrac{3}{3})$

$Centroid=(\dfrac{1}{3},1)$

Therefore the coordinates of the intersection of the medians of △ABC is (1/3, 1).

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3 years ago

Ilya [14]

Answer:

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Step-by-step explanation:

6 0

3 years ago

Leto [7]

6x5=30/2=(15)
2x3=6
15-6=11
11 is the answer

5 0

3 years ago

Aleks [24]

I think the answer would be 6

8 0

3 years ago

Keith_Richards [23]

The second option, 3/4 = 9/12 is a proportion.

Hope this helped! :D

8 0

3 years ago