Question

(PLEASE HELP! WILL VOTE BRAINLIEST) The table below shows four systems of equations: System 1 System 2 System 3 System 4 4x − 5y = 2 3x − y = 4 4x − 5y = 2 10x − 21y = 10 4x − 5y = 2 24x − 47y = 22 4x − 5y = 2 10x + 3y = 15 Which pair of systems will have the same solution?

Answer 1

Answer:

system 2 and system 3 have the same solution.

Step-by-step explanation:

system 1:

$4x-5y=2$

$3x-y=4$

we'll solve the two equation by the method of elimintaion to get the value of x and y.

on solving we get $x=\frac{18}{11} ,y=\frac{10}{11}$.

system 2:

$4x-5y=2\\10x-21y=10$

on solving the above two equation by the method of elimination we get the value of x and y.

on solving we get $x=\frac{-4}{17},y=\frac{-10}{17}$.

system 3:

$4x-5y=2\\24x-47y=22$

on solving the above two equation by the method of elimination we get the value of x and y.

on solving we get $x=\frac{-4}{17} ,y=\frac{-10}{17}$.

system 4:

$4x-5y=2\\10x+3y=15$

on solving the above two equation by the method of elimination we get the value of x and y.

on solving we get $x=\frac{81}{62} ,y=\frac{20}{31}$.

on looking for the solution of all the four system we see that system 2 and system 3 have the same value for x and y.

Hence, system 2 and system 3 have the same solution.

Answer 2

The answer is System 2 and system 3, because the second equation in system 3 is obtained by adding the first equation in system 2 to two times the second equation in system 2, i just took the test.