Solve for y.

Angela is buying a dress that is on sale for 20% off. If the original price of the dress is $40.00, how much money is Angela sav

neonofarm [45]

The answer is D, 8$. One easy way to do it is to take 10% of 40, which is 4, and double it.

8 0

3 years ago

Which infinite geometric series can you NOT find the sum?

Oksanka [162]

Answer: C) 127, 152.4, 182.88, 219.456,...

Step-by-step explanation:

You can only find the sum of an infinite geometric sequence if it converges.

One criterion to see if the series converges is if:

aₙ < aₙ₋₁

This means that, as n increases, the value of the terms decreases.

This means that as n tends to infinity, aₙ tends to zero.

Then we only can find the sum of those series where the terms are decreasing.

in A, B and D the terms are decreasing, then we can find the sum of those 3 series.

Now in the case of C, the terms are increasing, then we can not find the sum of that series.

4 0

3 years ago

1. A report from the Secretary of Health and Human Services stated that 70% of single-vehicle traffic fatalities that occur at n

Nuetrik [128]

Using the binomial distribution, it is found that there is a 0.7215 = 72.15% probability that between 10 and 15, inclusive, accidents involved drivers who were intoxicated.

For each fatality, there are only two possible outcomes, either it involved an intoxicated driver, or it did not. The probability of a fatality involving an intoxicated driver is independent of any other fatality, which means that the binomial distribution is used to solve this question.

Binomial probability distribution

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$C_{n,x} = \frac{n!}{x!(n-x)!}$

The parameters are:

x is the number of successes.
n is the number of trials.
p is the probability of a success on a single trial.

In this problem:

70% of fatalities involve an intoxicated driver, hence $p = 0.7$ .

A sample of 15 fatalities is taken, hence $n = 15$ .

The probability is:

$P(10 \leq X \leq 15) = P(X = 10) + P(X = 11) + P(X = 12) + P(X = 13) + P(X = 14) + P(X = 15)$

Hence

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 10) = C_{15,10}.(0.7)^{10}.(0.3)^{5} = 0.2061$

$P(X = 11) = C_{15,11}.(0.7)^{11}.(0.3)^{4} = 0.2186$

$P(X = 12) = C_{15,12}.(0.7)^{12}.(0.3)^{3} = 0.1700$

$P(X = 13) = C_{15,13}.(0.7)^{13}.(0.3)^{2} = 0.0916$

$P(X = 14) = C_{15,14}.(0.7)^{14}.(0.3)^{1} = 0.0305$

$P(X = 15) = C_{15,15}.(0.7)^{15}.(0.3)^{0} = 0.0047$

Then:

$P(10 \leq X \leq 15) = P(X = 10) + P(X = 11) + P(X = 12) + P(X = 13) + P(X = 14) + P(X = 15) = 0.2061 + 0.2186 + 0.1700 + 0.0916 + 0.0305 + 0.0047 = 0.7215$

0.7215 = 72.15% probability that between 10 and 15, inclusive, accidents involved drivers who were intoxicated.

A similar problem is given at brainly.com/question/24863377

5 0

3 years ago

Simplify. 13(−32.48−14.02) Enter your answer, as a decimal to tenths, in the box.

Artyom0805 [142]

If you mean 1/3 the answer is -15.5

1/3(-32.48-14.02) = 1/3(-46.5) = (-15.5)

3 0

3 years ago

What is the mean weight ___ pounds ?

natulia [17]

It is 84 ibs
Explanation
It’s actually easy if you learn 5 minutes of it
But thats the correct answer

8 0

3 years ago