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Bingel [31]
3 years ago
14

Brainly to whomever somehow solves for x. I WILL REPORT SCAMS AND UNHELPFUL "WHAT?" ANSWERS.

Mathematics
1 answer:
cestrela7 [59]3 years ago
3 0

Answer:

x=\frac{33}{7}

Step-by-step explanation:

Since ED is parallel to CA, the two triangles in the figure share all 3 angles and therefore must be similar. By definition, the corresponding sides of similar polygons are in a constant proportion.

Therefore, we have:

\frac{11}{11+x}=\frac{14}{20},\\14(11+x)=20\cdot 11,\\11+x=\frac{20\cdot 11}{14},\\x=\frac{110}{7}-11=\boxed{\frac{33}{7}}

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3 years ago
4/5 divided by 1/3 plus 1/5 minus 3/5
r-ruslan [8.4K]

Answer:

  \frac{\frac{4}{5}}{\frac{1}{3}+\frac{1}{5}-\frac{3}{5}}=-12

Step-by-step explanation:

Considering the expression

\frac{\frac{4}{5}}{\frac{1}{3}+\frac{1}{5}-\frac{3}{5}}

Solution Steps:

\frac{\frac{4}{5}}{\frac{1}{3}+\frac{1}{5}-\frac{3}{5}}

as

\mathrm{Combine\:the\:fractions\:}\frac{1}{5}-\frac{3}{5}:\quad -\frac{2}{5}

so

=\frac{\frac{4}{5}}{\frac{1}{3}-\frac{2}{5}}    

\mathrm{Apply\:the\:fraction\:rule}:\quad \frac{\frac{b}{c}}{a}=\frac{b}{c\:\cdot \:a}

=\frac{4}{5\left(\frac{1}{3}-\frac{2}{5}\right)}

join  \frac{1}{3}-\frac{2}{5}:\quad -\frac{1}{15}

so

=\frac{4}{5\left(-\frac{1}{15}\right)}

\mathrm{Remove\:parentheses}:\quad \left(-a\right)=-a

=\frac{4}{-5\cdot \frac{1}{15}}

\mathrm{Apply\:the\:fraction\:rule}:\quad \frac{a}{-b}=-\frac{a}{b}

=-\frac{4}{5\cdot \frac{1}{15}}

\mathrm{Multiply\:}5\cdot \frac{1}{15}\::\quad \frac{1}{3}

so

=-\frac{4}{\frac{1}{3}}

\mathrm{Simplify}\:\frac{4}{\frac{1}{3}}:\quad \frac{12}{1}

so

=-\frac{12}{1}

\mathrm{Apply\:rule}\:\frac{a}{1}=a

=-12

Therefore

                  \frac{\frac{4}{5}}{\frac{1}{3}+\frac{1}{5}-\frac{3}{5}}=-12

4 0
3 years ago
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Alenkinab [10]
System of Linear Equations entered :

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Graphic Representation of the Equations :

-6y + 5x = 7 -7y + 6x = 8

Solve equation [2] for the variable x


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[2] x = 7y/6 + 4/3
// Plug this in for variable x in equation [1]

[1] 5•(7y/6+4/3) - 6y = 7
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[1] - y = 2
// Solve equation [1] for the variable y


[1] y = - 2
// By now we know this much :

x = 7y/6+4/3
y = -2
// Use the y value to solve for x

x = (7/6)(-2)+4/3 = -1
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