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3 years ago

Alicia buys a 5 pound bag of rocks for a fish tank she uses 1 1/8 pounds for a small fish bowl how much is left

Mathematics

1 answer:

antiseptic1488 [7]3 years ago

5 0

Alicia would have 3 7/8 pound of rocks leftover

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Jenny uses a roller to paint a wall. The roller has a radius of 1.75 inches and a height of 10 inches. In two rolls, what is the

Katen [24]

Answer:

The area of the wall that she will paint in two rolls is <u>219.8 inches²</u>.

Step-by-step explanation:

Given:

Jenny uses a roller to paint a wall. The roller has a radius of 1.75 inches and a height of 10 inches.

Now, to find the area of the wall that she will paint in two rolls.

So, we find the lateral surface area of roller.

Radius (r) = 1.75 inches.

Height (h) = 10 inches.

So, to get the lateral surface area we put formula:

$A_{L} =2\pi rh$

$A_L=2\times 3.14\times 1.75\times 10$

$A_L=109.9\ inches^2.$

Thus, the lateral surface area of the roller = 109.9 inches².

Now, to get the area of wall that she will paint in two rolls we multiply 2 by the lateral surface area of the roller:

$109.9\times 2\\\\=219.8\ inches^2.$

Therefore, the area of the wall that she will paint in two rolls is 219.8 inches².

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3 years ago

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Diyva has 70 rocks.she donates half of the rocks to a science center. then she collects 3 rocks on each of her nature hikes

lubasha [3.4K]

Answer:

What are you asking here? This is more like a statement.

Step-by-step explanation:

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2 years ago

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Select all the expressions equivalent to (4x⁵)(5x⁶).

Liula [17]

Step-by-step explanation:

$= 4 {x}^{5} \times 5 {x}^{6}$

$= (4 \times 5) {x}^{5 + 6}$

$= 20 {x}^{11}$

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2 years ago

A rock thrown vertically upward from the surface of the moon at a velocity of 36m/sec reaches a height of s = 36t - 0.8 t^2 met

Verdich [7]

Answer:

a. The rock's velocity is $v(t)=36-1.6t \:{(m/s)}$ and the acceleration is $a(t)=-1.6 \:{(m/s^2)}$

b. It takes 22.5 seconds to reach the highest point.

c. The rock goes up to 405 m.

d. It reach half its maximum height when time is 6.59 s or 38.41 s.

e. The rock is aloft for 45 seconds.

Step-by-step explanation:

Velocity is defined as the rate of change of position or the rate of displacement. $v(t)=\frac{ds}{dt}$
Acceleration is defined as the rate of change of velocity. $a(t)=\frac{dv}{dt}$

The rock's velocity is the derivative of the height function $s(t) = 36t - 0.8 t^2$

$v(t)=\frac{d}{dt}(36t - 0.8 t^2) \\\\\mathrm{Apply\:the\:Sum/Difference\:Rule}:\quad \left(f\pm g\right)'=f\:'\pm g'\\\\v(t)=\frac{d}{dt}\left(36t\right)-\frac{d}{dt}\left(0.8t^2\right)\\\\v(t)=36-1.6t$

The rock's acceleration is the derivative of the velocity function $v(t)=36-1.6t$

$a(t)=\frac{d}{dt}(36-1.6t)\\\\a(t)=-1.6$

b. The rock will reach its highest point when the velocity becomes zero.

$v(t)=36-1.6t=0\\36\cdot \:10-1.6t\cdot \:10=0\cdot \:10\\360-16t=0\\360-16t-360=0-360\\-16t=-360\\t=\frac{45}{2}=22.5$

It takes 22.5 seconds to reach the highest point.

c. The rock reach its highest point when t = 22.5 s

Thus

$s(22.5) = 36(22.5) - 0.8 (22.5)^2\\s(22.5) =405$

So the rock goes up to 405 m.

d. The maximum height is 405 m. So the half of its maximum height = $\frac{405}{2} =202.5 \:m$

To find the time it reach half its maximum height, we need to solve

$36t - 0.8 t^2=202.5\\36t\cdot \:10-0.8t^2\cdot \:10=202.5\cdot \:10\\360t-8t^2=2025\\360t-8t^2-2025=2025-2025\\-8t^2+360t-2025=0$

For a quadratic equation of the form $ax^2+bx+c=0$ the solutions are

$x_{1,\:2}=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$

$\mathrm{For\:}\quad a=-8,\:b=360,\:c=-2025:\\\\t=\frac{-360+\sqrt{360^2-4\left(-8\right)\left(-2025\right)}}{2\left(-8\right)}=\frac{45\left(2-\sqrt{2}\right)}{4}\approx 6.59\\\\t=\frac{-360-\sqrt{360^2-4\left(-8\right)\left(-2025\right)}}{2\left(-8\right)}=\frac{45\left(2+\sqrt{2}\right)}{4}\approx 38.41$

It reach half its maximum height when time is 6.59 s or 38.41 s.

e. It is aloft until s(t) = 0 again

$36t - 0.8 t^2=0\\\\\mathrm{Factor\:}36t-0.8t^2\rightarrow -t\left(0.8t-36\right)\\\\\mathrm{The\:solutions\:to\:the\:quadratic\:equation\:are:}\\\\t=0,\:t=45$

The rock is aloft for 45 seconds.

5 0

3 years ago

When Jake took his dog, Rocky, to the vet in December, Rocky weighed 29 pounds 9 ounces. When he took Rocky back to the vet in M

faust18 [17]

Answer:

he gained 3 pounds :)

Step-by-step explanation:

also im not really sure about the ounces!!!

7 0

2 years ago