R = { (x,y): 3x-y=0 }
The condition is 3x=y so that's not going to be any of these things.
R is reflexive if (x,x)∈R for all x. Let's check.
3x - y = 3x - x = 2x ≠ 0 necessarily. NOT REFLEXIVE
R is symmetric if (x,y)∈R → (y,x)∈R. Let's check.
(x,y)∈R so
3x-y = 0
y = 3x
Is (y,x)∈R. That would be true if 3y-x=0
3y - x = 3(3x) - x = 8x ≠ 0 necessarily NOT SYMMETRIC
R is transitive if (x,y)∈R and (y,z)∈R → (x,z)∈R. Let's check.
3x-y = 0 so y=3x
3y-z = 0 so z=3y = 9x
3x - z = 3x - 9x = -6x ≠ 0 necessarily NOT TRANSITIVE
5∧2(exponent of 2) - 1 =24
Answer:
Annual deposit= $3,474.39
Explanation:
Giving the following information:
You want to have $60,000 in your savings account 12 years from now, and you’re prepared to make equal annual deposits into the account at the end of each year. The account pays 6.4 percent interest.
FV= {A*[(1+i)^n-1]}/i
A= annual deposit
Isolating A:
A= (FV*i)/{[(1+i)^n]-1}
A= (60,000*0.064)/[(1.064^12)-1]= $3,474.39
plz mark brainly
Line A: 2x+2y=8 ⇒2y=-2x+8 ⇒ y=-x+4
Line B: x+y=3 ⇒y=-x+3
Therefore: y=y then:
-x+4=-x+3
-x+x=3-4
0≠-1 ⇒There is no solution because the lines are parallels
Answer: There is no solution
