The linear model for the data is expressed as: R = 20p - 160.
<h3>How to Write a Linear Model?</h3>
Using two pairs of values from the table values, say, (32, 480) and (33, 500), find the unit rate (m).
Unit rate (m) = (500 - 480)/(33 - 32) = 20/1
Unit rate (m) = 20.
Substitute (p, R) = (32, 480) and m = 20 into R = mp + b to find b
480 = 20(32) + b
480 = 640 + b
480 - 640 = b
b = -160
To write the linear model, substitute m = 20 and b = -160 into R = mp + b:
R = 20p - 160
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Answer:
1.45
Step-by-step explanation:
not sure but trying to help :)
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Answer:
7c+21
Step-by-step explanation:
multiply 7 by c and 7 times 3
7c and 21
7c+21
Answer:
a) The differential equation for the velocity is given by
(dv/dt) = k(250 - v)
b) v(t) = 250 - e⁽⁵•⁵² ⁻ ᵏᵗ⁾
With units of km/h
Step-by-step explanation:
Acceleration, a ∝ (250 - v)
But acceleration is widely given as dv/dt
(dv/dt) ∝ (250 - v)
(dv/dt) = k(250 - v)
where k = constant of proportionality
(dv/dt) = k(250 - v)
b) (dv/dt) = k(250 - v)
dv/(250 - v) = k dt
∫ dv/(250 - v) = ∫ k dt
- In (250 - v) = kt + c (where c is the constant of integration)
v(0) = 0; meaning, at t = 0, v = 0
- In 250 = 0 + C
c = - In 250 = - 5.52
- In (250 - v) = kt - 5.52
In (250 - v) = 5.52 - kt
250 - v = e⁽⁵•⁵² ⁻ ᵏᵗ⁾
v = 250 - e⁽⁵•⁵² ⁻ ᵏᵗ⁾
With units of km/h
i hope this work for you
and sory if im wrang
