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4 years ago

Find the first three terms of f(n + 1) = f(n) + 8, if f(1) = 27.

Mathematics

1 answer:

dezoksy [38]4 years ago

3 0

I hope this helps you

f (1+1)= f (1)+8

f (2)= 27+8

f (2)=35

f (2+1)= f (2)+8

f (3)= 35+8

f (3)=43

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Find the area of quadrilateral KLMN

WITCHER [35]

Step-by-step explanation:

I just answered this ...

the first thing we notice : the quadrilateral has 2 pairs of equally long sides with 2 angles being openly 90°.

so, we are dealing with a rectangle here.

we know that one pair of the sides (NK = LM) are 24 cm long.

and we know that KL:LM = 3:4.

that means that the pair KL = MN are the shorter sides of the rectangle. and their length is according to the ratio 3/4 of NK=LM.

3/4 × 24 = 18 cm

the area of that rectangle is therefore

18 × 24 = 432 cm²

6 0

3 years ago

In triangle ABC mzA -45, mzB = 40", and a = 7. Which equation should you<br> solve to find b?

yaroslaw [1]

Answer:

Option A. $\frac{sin(45\°)}{7}=\frac{sin(40\°)}{b}$

Step-by-step explanation:

we know that

Applying the law of sines in the triangle ABC

$\frac{sin(A)}{a}=\frac{sin(B)}{b}$

substitute the given values

$\frac{sin(45\°)}{7}=\frac{sin(40\°)}{b}$

$b=\frac{7}{sin(45\°)}sin(40\°)\\\\b=6.4\ units$

6 0

3 years ago

The taxiways and runways of a major airport are carefully monitored to expedite takeoffs and landings and to prevent collisions.

tatyana61 [14]

Answer:

18.04% probability that exactly 3 serious deviations and incursions will occur at LAX in a randomly selected year

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

In which

x is the number of sucesses

e = 2.71828 is the Euler number

$\mu$ is the mean in the given time interval.

Suppose the mean number of deviations and incursions per year at the Los Angeles International Airport (LAX) is 2.

This means that $\mu = 2$

Find the probability that exactly 3 serious deviations and incursions will occur at LAX in a randomly selected year

This is P(X = 3).

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

$P(X = 3) = \frac{e^{-2}*2^{3}}{(3)!} = 0.1804$

18.04% probability that exactly 3 serious deviations and incursions will occur at LAX in a randomly selected year

4 0

3 years ago

Five divided sixty eight

Schach [20]

5/68, or about 0.07

8 0

3 years ago

0.000 000 000 000 25 (120 000 000 000 000)(5 000 000 000 000 000 000 )

maksim [4K]

I think you’re on the right track

7 0

3 years ago