Answer:
m∠1= 80
m∠2= 100
m∠3= 80
Step-by-step explanation:
Given: m∠1= 2x +40
m∠2= 2y +40
m∠3= x +2y
m∠1 +m∠2= 180 (adj. ∠s on a str. line)
2x +40 +2y +40= 180
2x +2y+ 80= 180
2x +2y= 180 -80
2x +2y= 100
2(x +y)= 100
x +y= 100 ÷2
x +y= 50 -----(1)
m∠1= m∠3 (vert. opp. ∠s)
2x +40= x +2y
2x -x +40= 2y
x= 2y -40 -----(2)
Substitute equation (2) into (1):
2y -40 +y= 50
3y= 50 +40
3y= 90
y= 90 ÷3
y= 30
Substitute y= 30 into equation (2):
x= 2(30) -40
x= 60 -40
x= 20
m∠1
= 2x +40
= 2(20) +40
= 40 +40
= 80
m∠2
= 2y +40
= 2(30) +40
= 60 +40
= 100
m∠3
= x +2y
= 20 +2(30)
= 20 +60
= 80
Alternatively, since m∠1= m∠3,
m∠3
= m∠1 (vert. opp. ∠s)
= 80
Answer:
2x + .8 = 58.9
His number, x, is 29.05
Step-by-step explanation:
2x + .8 = 58.9
2x = 58.1
x = 29.05
Answer:
2.729
3.4052
3.45
3.5
Step-by-step explanation:
Answer:
yes
Step-by-step explanation:
It is possible to design more than one flag with these lengths because the two smaller side length 27 and 40 is greater than 50 which is larger side length.
Answer
1360
Step-by-step explanation:
4x10 is 40 so you'd have to multiply 40x34 which is 1360
