All categories

3 years ago

List 3 integers that are > -4

Mathematics

1 answer:

adell [148]3 years ago

3 0

For this you could name any positive number, 0, or -3,-2,-1.
ex.
2,3,-2

You might be interested in

Find the partial fraction decomposition of the rational expression with prime quadratic factors in the denominator

SpyIntel [72]

$\dfrac{5x^4-7x^3-12x^2+6x+21}{(x-3)(x^2-2)^2}=\dfrac{a_1}{x-3}+\dfrac{a_2x+a_3}{x^2-2}+\dfrac{a_4x+a_5}{(x^2-2)^2}$
$\implies 5x^4-7x^3-12x^2+6x+21=a_1(x^2-2)^2+(a_2x+a_3)(x-3)(x^2-2)+(a_4x+a_5)(x-3)$

When $x=3$ , you're left with

$147=49a_1\implies a_1=\dfrac{147}{49}=3$

When $x=\sqrt2$ or $x=-\sqrt2$ , you're left with

$\begin{cases}17-8\sqrt2=(\sqrt2a_4+a_5)(\sqrt2-3)&\text{for }x=\sqrt2\\17+8\sqrt2=(-\sqrt2a_4+a_5)(-\sqrt2-3)\end{cases}\implies\begin{cases}-5+\sqrt2=\sqrt2a_4+a_5\\-5-\sqrt2=-\sqrt2a_4+a_5\end{cases}$

Adding the two equations together gives $-10=2a_5$ , or $a_5=-5$ . Subtracting them gives $2\sqrt2=2\sqrt2a_4$ , $a_4=1$ .

Now, you have

$5x^4-7x^3-12x^2+6x+21=3(x^2-2)^2+(a_2x+a_3)(x-3)(x^2-2)+(x-5)(x-3)$
$5x^4-7x^3-12x^2+6x+21=3x^4-11x^2-8x+27+(a_2x+a_3)(x-3)(x^2-2)$
$2x^4-7x^3-x^2+14x-6=(a_2x+a_3)(x-3)(x^2-2)$

By just examining the leading and lagging (first and last) terms that would be obtained by expanding the right side, and matching these with the terms on the left side, you would see that $a_2x^4=2x^4$ and $a_3(-3)(-2)=6a_3=-6$ . These alone tell you that you must have $a_2=2$ and $a_3=-1$ .

So the partial fraction decomposition is

$\dfrac3{x-3}+\dfrac{2x-1}{x^2-2}+\dfrac{x-5}{(x^2-2)^2}$

7 0

3 years ago

Need help asap today by 5<br>

WINSTONCH [101]

Answer:

I put a photo of the answers.

Step-by-step explanation:

For the problems, I turned the whole under into a fraction, flipped the second fraction and multiplied.

7 0

3 years ago

ABCD is a rhombus. Find AB. Give answer as a fraction in simplest form.<br>

LuckyWell [14K]

Answer:

The length of AB = 97/3 units

Step-by-step explanation:

The length of CD = 7x+2

The length of BC = 4x+15

We know that a rhombus is a quadrilateral whose four sides all have the same length.

Thus, the equation becomes

7x+2 = 4x+15

7x-4x = 15-2

3x = 13

x = 13/3

So, the length of CD = 7x+2 = 7(13/3)+2

= 91/3 + 2

= 97/3

And, the length of BC = 4x+15 = 4(13/3) + 15

= 97/3

We already know that a rhombus is a quadrilateral whose four sides all have the same length.

Thus, the length of AB = 97/3 units

5 0

3 years ago

Read 2 more answers

When it is raining outside, you tend to stay in and watch TV. The number of hours of TV that you watch in a given week is twice

Juli2301 [7.4K]

Answer:

Step-by-step explanation:

the answer is 74

7 0

4 years ago

Cual es el numero que hace falta en la sucesión de 0,2,6,22_,114,202

Romashka-Z-Leto [24]

Answer:

Step-by-step explanation:

6 0

3 years ago