If 8 out of 20 students in a class are boys,what percent of the class is made up of boys

Mathematics

1 answer:

lara31 [8.8K]3 years ago

3 0

Answer:

40%

Step-by-step explanation:

First, divide 100 by 20. You do this because you need something out of 100 to equal a percent. (Example- 50 out of 100 is 50%)

Next you need to take the number you got from dividing (5) and multiply that with 8. This leaves you with 40/100 or 40%.

Hope this helps!

-Coconut;)

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consuela's living room is a rectangle with an area of 360 square feet. the width of the living room is 5/8 its length. what is t

Aleks [24]

Area of Consuela's rectangular living room = 360 square feet
Let us assume the the length of the living room = x
Then
width of the living room = (5/8) * x
= (5x/8)
Then
Area of the rectangle = Length * Width
360 = x * (5x/8)
360 = 5x^2/8
2880 = 5x^2
x^2 = 2880/5
x^2 = 576
x^2 = (24)^2 inches
x = 24
Then
The length of the rectangle is = 24 inches
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skelet666 [1.2K]

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Step-by-step explanation:

y=-x2+6x-8

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Solve (1/81)^x*1/243=(1/9)^−3−1 by rewriting each side with a common base.

elena55 [62]

Answer:

$x=(243)log_{\frac{1}{81}}[(\frac{1}{81})-1]$

Step-by-step explanation:

you have the following formula:

$(\frac{1}{81})^{\frac{x}{243}}=(\frac{1}{9})^{-3}-1$

To solve this equation you use the following properties:

$log_aa^x=x$

Thne, by using this propwerty in the equation (1) you obtain for x

$log_{(\frac{1}{81})}(\frac{1}{81})^{\frac{x}{243}}=log_{\frac{1}{81}}[(\frac{1}{81})-1]\\\\\frac{x}{243}=log_{\frac{1}{81}}[(\frac{1}{81})-1]\\\\x=(243)log_{\frac{1}{81}}[(\frac{1}{81})-1]$