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dalvyx [7]
2 years ago
9

Please help with this question (I will mark brainliest) Thank u >u<

Mathematics
1 answer:
likoan [24]2 years ago
5 0

Answer:

Im Not 100% but, I will give you the best answer.

I think it might be Option 3

If not, (give me 1 star)

I tried

Step-by-step explanation:

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Total power generated by wind worldwide doubles every 3 years. In a particular year, the world wind-generating capacity was abou
IceJOKER [234]
<span>You are given the sum of the power created by wind worldwide which doubles every 3 years. In one an unknown year, the world wind generating capacity was about 91 thousand megawatts. You are asked for the growth rate. the growth rate formula is given below:

growth rate = (present / past)^(1/n)
2 = (present/91MW)^(1/3)
the present power is 728MW</span>
7 0
3 years ago
Shino says the formula to calculate the volume of the prism is V=Bh where B is the area of the base.Angelo says the formula is V
Kruka [31]

Answer:

  it depends

Step-by-step explanation:

<em>Shino's formula will work for any prism</em>.

Angelo's formula will work for any prism whose base area can be found by ...

  B = (1/2)ew

<em>Angelo can use this formula for a triangular prism</em>.

__

For a triangular prism, both may be correct.

For a prism of another shape, Shino is correct. (Angelo may also be correct, depending on the variable definitions.)

5 0
3 years ago
you make homemade lip balm about 11% of the lip balm is made from beeswax you make 4 2/5 teaspoons of of the lip balm about how
o-na [289]
≈ 1/2 teaspoon
4 2/5 * .11 = .484 teaspoon
7 0
3 years ago
The normal distribution An automobile battery manufacturer offers a 31/54 warranty on its batteries. The first number in the war
seraphim [82]

Answer:

1) if the manufacturer's assumptions are correct, it would reed to replace 0.62% of its batteries free.

2) a standard deviation of 6.0843 results in a 1.07% replacement rate

3) using the revised standard deviation for battery life, 91.9% of the manufacturer's batteries don't get free replacement but qualifies for the prorated credit

Step-by-step explanation:

based on the given data;

x will represent the random variable such that the lifetime of its auto batteries, is normally distributed with a mean of 45 months and a standard deviation of 5.6 months

so

x → N( U = 45, ∝ = 5.6)

Under the warranty, if a battery fails within 31 months of purchase, the manufacturer replaces the battery at no charges to the consumer.

if the battery fails after 31 months but within 54 months, the manufacturer provides a prostrated credit towards the purchase of anew battery

1) If the manufacturer's assumptions are correct,

p(x < 3) = p( [x-u / ∝ ] < [ 31-45 / 5.6] )

= p( z < -2.5 )

using the standard normal table,

value of z = 0.0062 ≈ 0.62%

so if the manufacturer's assumptions are correct, it would reed to replace 0.62% of its batteries free.

2)

The company finds that it is replacing 1.07% of its batteries free of charge. It suspects that its assumption standard deviation of the life of its batteries is incorrect, so a standard deviation of ? results in a 1.07%

so lets say;

p ( x < 31 ) = ( 1.07%) = 0.0107

p ( [x-u / ∝ ] < [ 31-45 / ∝] ) = 0.0107

now from the standard table

-2.301 is 1.07%

so

( 31 - 45 / ∝ ) = -2.301

-14 / ∝ = -2.301

∝ = -14 / - 2.301

∝ = 6.0843

therefore a standard deviation of 6.0843 results in a 1.07% replacement rate

3)

Using the revised standard deviation for battery life, what percentage of the manufacturer's batteries don't free replacement but do qualify for the prorated credit?

p( 31 < x < 54 ) = p ( [31 - u / ∝ ] < [ x-u / ∝]  < [ 54 - 45 / ∝] )

= p ( [31 - 45 / 6.0843 ] < [ x-u / ∝]  < [ 54 - 45 / 6.0843] )

= p ( -2.301 < z < 1.4792 )

= p(Z < 1.5) - p(Z < -2.3)

= 0.9393 - 0.0108

= 0.919 ≈ 91.9%

therefore using the revised standard deviation for battery life, 91.9% of the manufacturer's batteries don't get free replacement but qualifies for the prorated credit

8 0
3 years ago
Your middle school has 900 students. 1/3 of students bring their lunch instead of buying lunch at school. What is the value of t
Sholpan [36]
Hey there! 
This may seem pretty scary because, duh, fractions, big numbers, MATH.
However, you've just got to break it down.
So first, we find out how many students BRING lunch.
To find 1/3 of 900, you just multiply 900 by 1/3. \frac{900}{1} *  \frac{1}{3} 
BUT WE CAN SIMPLIFY: to 300/1 times 1/1, which is 300/1.
So 300 people BRING lunch.
Now, to find people who BUY lunch, you just subtract the number of people who bring lunch by the total number of people.
900
-300
600 
So 600 people BUY lunch.
All that's left to do is turn all these numbers into a ratio.
Easy peasy: put 300 and 600 like a fraction, like so:
\frac{300}{600}
Hope this helped! ;)


6 0
3 years ago
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