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Colt1911 [192]
3 years ago
9

Please help me with these 19 and 20 and tell me what you use to get the answer

Mathematics
2 answers:
ss7ja [257]3 years ago
6 0
36 + h = 75...subtract 36 from both sides
h = 75 - 36
h = 39

-176 = h + (-219)
-176 = h - 219....add 219 to both sides
219 - 176 = h
43 = h
vaieri [72.5K]3 years ago
5 0
36+h=75   (subtract 36 from both sides in order to find h)
h=75-36
h=39

-176=h+(-219)
-176=h-219    (add 219 to both sides in order to solve for h)
43=h
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Angles R and J are corresponding angles. The measure of R is 50°. What is the measure of J?
rosijanka [135]
B.40 if angles are corresponding that means they add up to be 90 degrees and 50 plus 40 equals 90
6 0
3 years ago
Gabriel buys 5 pounds of apples for $8. Allie buys 10 pounds of the same apples for $16. Which of the following points is NOT on
Tom [10]
I don't understand your question
4 0
4 years ago
Liam has to fill a hole in the ground that is 24 inches deep. He fills the hole at a rate of 6 inches in 30 minutes. Write a fun
kupik [55]

Answer:

The function that models the depth of the hole in feet over time in hours is h(t) = 24 - 12\cdot t.

Step-by-step explanation:

According to the statement, the variable to be modelled is the depth of the hole, which decreases whereas is filled. Under the assumption that the hole is filled at constant rate, we obtain the following expression:

h(t) = h_{o}-\frac{\Delta h}{\Delta t}\cdot t (1)

Where:

h(t) - Current depth of the hole, measured in inches.

h_{o} - Initial depth of the hole, measured in inches.

\Delta h - Filled level, measured in inches.

\Delta t - Filling time, measured in hours.

t - Time, measured in hours.

If we know that h_{o} = 24\,in, \Delta h = 6\,in and \Delta t = 0.5\,h, then the function that models the depth of the hole is:

h(t) = 24 - 12\cdot t

The function that models the depth of the hole in feet over time in hours is h(t) = 24 - 12\cdot t.

6 0
3 years ago
Two standardized​ tests, a and​ b, use very different scales of scores. the formula upper a equals 40 times upper b plus 50a=40×
Leona [35]
Adding (or subtracting) a constant to every data value adds (or subtracts) the same constant to measures of position such as center,percentiles, max or min.

Its shape and spread such as range, IQR, standard deviation remain unchanged.
When we multiply (or divide) all the data values by any constant, all measures of position (such as the mean, median, and percentiles) and measures of spread (such as the range, the IQR, and the standard deviation) are multiplied (or divided) by that same constant.
Part A:

The lowest score is a measure of location, so both addition and multiplying the lowest score of test B by 40 and adding 50 to the result will affect the lowest score of test A.

Thus, the lowest score of test A is given by 40(21) + 50 = 890

Therefore, the lowest score of test A is 890.



Part B:

The mean score is a measure of location, so both addition and multiplying the mean score of test B by 40 and adding 50 to the result will affect the lowest score of test A.

Thus, the mean score of test A is given by 40(29) + 50 = 1,210

Therefore, the mean score of test A is 890.



Part C:

The standard deviation is a measure of spread, so multiplying the standard deviation of test B by 40 will affect the standard deviation but adding 50 to the result will not affect the standard deviation of test A.

Thus, the standard deviation of test A is given by 40(2) = 80

Therefore, the standard deviation of test A is 80.



Part D

The Q3 score is a measure of location, so both addition and multiplying the Q3 score of test B by 40 and adding 50 to the result will affect the Q3 score of test A.

Thus, the Q3 score of test A is given by 40(28) + 50 = 1,170

Therefore, the Q3 score of test a is 1,170.



Part E:

The median score is a measure of location, so both addition and multiplying the median score of test B by 40 and adding 50 to the result will affect the median score of test A.

Thus, the median score of test A is given by 40(26) + 50 = 1,090

Therefore, the median score of test A is 1,090.



Part F:

The IQR is a measure of spread, so multiplying the IQR of test B by 40 will affect the IQR but adding 50 to the result will not affect the IQR of test A.

Thus, the IQR of test A is given by 40(6) = 240

Therefore, the IQR of test A is 240.
6 0
3 years ago
What is the inverse of function f? f(x)=10/9r+11
Rasek [7]

f(x) = \frac{10}{9}x + 11 \\

So :

y =  \frac{10}{9}x + 11 \\

Subtract the sides of the equation minus 11

y - 11 =  \frac{10}{9}x \\

Multiply the sides of the equation by 9

9(y - 11) = 10x

9y - 99 = 10x

Divided the sides of the equation by 10

\frac{9y - 99}{10} = x \\

So :

{f}^{ - 1}(x) =  \frac{9x - 99}{10} \\

_________________________________

And we're done.

Thanks for watching buddy good luck.

♥️♥️♥️♥️♥️

3 0
4 years ago
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