Answer:
Savings per can would be 0.02 cents when purchased in lots.
Step-by-step explanation:
Given:
Ordinary price of soup 2 cans = 0.33 cents.
When purchases in lots 12 cans = 1.74
We need to find the saving per can when purchased in Lots.
Solution:
Ordinary price of soup 2 cans = 0.33 cents.
1 can = Cost of 1 can when purchased ordinary.
By Using Unitary method we get;
Cost of 1 can when purchased ordinary = ![\frac{0.33}{2} = 0.165\ cents/can](https://tex.z-dn.net/?f=%5Cfrac%7B0.33%7D%7B2%7D%20%3D%200.165%5C%20cents%2Fcan)
Now we will find the Cost of 1 can when purchased in lot.
12 cans = 1.74
1 can = Cost of 1 can when purchase in lot.
Again by using Unitary method we get;
Cost of 1 can when purchase in lot = ![\frac{1.74}{12} = 0.145\ cents/can](https://tex.z-dn.net/?f=%5Cfrac%7B1.74%7D%7B12%7D%20%3D%200.145%5C%20cents%2Fcan)
Savings = Cost of 1 can when purchase in lot - Cost of 1 can when purchased ordinary
Savings = ![0.165-0.145=0.02\ cents/can](https://tex.z-dn.net/?f=0.165-0.145%3D0.02%5C%20cents%2Fcan)
Hence Savings per can would be 0.02 cents when purchased in lots.