Let f(x) = x² + 6x²-x+ 5 then ,
number to be added be P
then,
f(x) = x² + 6x²-x+ 5 +P
According to the qn,
(x+3) is exactly divisible by zero then,
R=0
comparing .. we get a= -3
now by remainder theorm
R=f(a)
0=f(-3)
0=(-3)² + 6(-3)²-(-3)+ 5 + P
0= 9 + 54 + 3 + 5 + P
-71=P
therefore, -71 should be added.
Hope you understand
The simple interest would be $210. I hope that helps!
Answer:
Unable to tell you
Step-by-step explanation:
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Alright! In order to solve this problem you need to know your keywords:
Sum = To add
Difference = Subtract
Product = To multiply
So! When it asks for the sum of 24 and 7 you add them:
24 + 7 = 31
The difference of 18 and 6:
18 - 6 = 12
The find the product of these two you simply multiply:
12 x 31 = 372!