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3 years ago

Question: Write a function for the line with a slope of 5 that passes through the point (2, 1).

2 answers:

6 0

Y=5x-9

Explanation:
y-y1=m(x-x1) Substitute the numbers in
y-1=5(x-2) Distribute the 5
y-1=5x-10 Add the 1 to both sides
y=5x-9

galben [10]3 years ago

6 0

The answer is y=5x-9

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The function f(x)=125(0.9)x models the population of a species of fly in millions after x years.

deff fn [24]

Answer: (B) 3 times as fast

<u>Step-by-step explanation:</u>

rate of change is the "slope" between the given interval.

f(x) = 125(.9)ˣ

f(1) = 125(.9)¹

= 112.5

f(5) = 125(.9)⁵

= 73.8

$\dfrac{f(5) - f(1)}{5 - 1} = \dfrac{73.8-112.5}{5-1} = -\dfrac{38.7}{4} = -9.675$

********************

f(11) = 125(.9)¹¹

= 39.2

f(15) = 125(.9)¹⁵

= 25.7

$\dfrac{f(15) - f(11)}{15 - 11} = \dfrac{39.2-25.7}{15-11} = -\dfrac{13.5}{4} = -3.375$

********************

The rate of change from years 1 to 5 is approximately 3 times the rate of change from years 11 to 15.

7 0

3 years ago

Daniel is climbing up a cliff at a rate of 2 meters per minute. What is his rate in feet per hour?

il63 [147K]

The answer is 394 feet per hour and also good luck to what ever you working on

6 0

3 years ago

A master painter can paint 110 square yards of surface area with a roller in 1 hour, while his apprentice can paint 85 square fe

7nadin3 [17]

The apprentice needs 6.25 hours to complete the job using the brush

<h3><u>Solution:</u></h3>

Given, A master painter can paint 110 square yards of surface area with a roller in 1 hour

$\text { Then, his rate of painting }=110 \text { yard }^{2}$

We know that 1 yard = 3 feet

$=110 \times(1 \text { yard })^{2}=110 \times(3 \text { feet })^{2}=110 \times 9 \text { feet }^{2}=990 \text { square feet. }$

While his apprentice can paint 85 square feet of surface area per hour with a brush

Together they are painting a building with a surface area of 5100 square feet.

After painting for $4\frac{1}{4}$ hours , the master painter lets the apprentice Finish the job.

Now, they worked for $4\frac{1}{4}$ hours

Then, area painted = area painted by master + area painted by apprentice

$\text { Area painted }=990 \text { square feet per hour } \times 4 \frac{1}{4} \text { hours }+85 \text { square feet per hour } \times 4 \frac{1}{4} \text { hours }$

$\text { Area painted }=990 \times \frac{4 \times 4+1}{4}+85 \times \frac{4 \times 4+1}{4}$

$\begin{array}{l}{\text { Area painted }=990 \times \frac{17}{4}+85 \times \frac{17}{4}=(990+85) \times \frac{17}{4}} \\\\ {\text { Area painted }=1075 \times \frac{17}{4}=4568.75 \text { square feet. }}\end{array}$