Answer:
Mean track length for this rock specimen is between 10.463 and 13.537
Step-by-step explanation:
99% confidence interval for the mean track length for rock specimen can be calculated using the formula:
M±
where
- M is the average track length (12 μm) in the report
- t is the two tailed t-score in 99% confidence interval (2.977)
- s is the standard deviation of track lengths in the report (2 μm)
- N is the total number of tracks (15)
putting these numbers in the formula, we get confidence interval in 99% confidence as:
12±
=12±1.537
Therefore, mean track length for this rock specimen is between 10.463 and 13.537
Answer:
n = 2
Step-by-step explanation:
-1 + 3 = 2
41-19 is 22 so he has 22 nickels. The amount of dimes is put in there to distract you. Just ignore those! :)
I believe four is the right answer to the problem
Answer: (P.s its very hard to write special characters here, i hope this helped though)
((−6d0)(g−3))(h2)
d−5m3g−2h5
=
−6d5g2h2
g3h5m3
=
−6d5
gh3m3