Pls help pls pls hii lol bye hahaha math fractions lol. videostar

Click on the graph below to create a quadrilateral with vertices at the following points. (-4,9), (-8,9), (-9,7), (-9, 4)

Shalnov [3]

Given (-4,9) (-8,9),(-9,7,(-9,4)

...

To Find : plot the point and draw quadrilateral

Solution:

(-4,9)

go 4 left of origin and then go 9 up

(-8,9)

go 8 left of origin and then go 8 up

(-9,7)

go 9 left of origin and then go 7 up

(-9,4)

go 9 left of origin and then go join (-4,9) with (-8,9) and (-9,4) 4 up

join (-9,7) with (-8,9) and (-9,4)

Quadrilateral is constructed

4 0

2 years ago

A farm stand sells apples pies and jars of applesauce. The table shows the number of apples needed to

lara31 [8.8K]

Answer:

IF I am correct, 5

Step-by-step explanation:

98/ 18

8 0

3 years ago

9. A circle has an arc of length 56pi that is intercepted by a central angle of 120 degrees. What is the radius of the circle?

SSSSS [86.1K]

Answer:

Part 4) $r=84\ units$

Part 9) $sin(\theta)=-\frac{\sqrt{5}}{3}$

Part 10) $sin(\theta)=-\frac{9\sqrt{202}}{202}$

Step-by-step explanation:

Part 4) A circle has an arc of length 56pi that is intercepted by a central angle of 120 degrees. What is the radius of the circle?

we know that

The circumference of a circle subtends a central angle of 360 degrees

The circumference is equal to

$C=2\pi r$

using proportion

$\frac{2\pi r}{360^o}=\frac{56\pi}{120^o}$

simplify

$\frac{r}{180^o}=\frac{56}{120^o}$

solve for r

$r=\frac{56}{120^o}(180^o)$

$r=84\ units$

Part 9) Given cos(∅)=-2/3 and ∅ lies in Quadrant III. Find the exact value of sin(∅) in simplified form

Remember the trigonometric identity

$cos^2(\theta)+sin^2(\theta)=1$

we have

$cos(\theta)=-\frac{2}{3}$

substitute the given value

$(-\frac{2}{3})^2+sin^2(\theta)=1$

$\frac{4}{9}+sin^2(\theta)=1$

$sin^2(\theta)=1-\frac{4}{9}$

$sin^2(\theta)=\frac{5}{9}$

square root both sides

$sin(\theta)=\pm\frac{\sqrt{5}}{3}$

we know that

If ∅ lies in Quadrant III

then

The value of sin(∅) is negative

$sin(\theta)=-\frac{\sqrt{5}}{3}$

Part 10) The terminal side of ∅ passes through the point (11,-9). What is the exact value of sin(∅) in simplified form?

see the attached figure to better understand the problem

In the right triangle ABC of the figure

$sin(\theta)=\frac{BC}{AC}$

Find the length side AC applying the Pythagorean Theorem

$AC^2=AB^2+BC^2$

substitute the given values

$AC^2=11^2+9^2$

$AC^2=202$

$AC=\sqrt{202}\ units$

so

$sin(\theta)=\frac{9}{\sqrt{202}}$

simplify

$sin(\theta)=\frac{9\sqrt{202}}{202}$

Remember that

The point (11,-9) lies in Quadrant IV

then

The value of sin(∅) is negative

therefore

$sin(\theta)=-\frac{9\sqrt{202}}{202}$

5 0

3 years ago

Find cos0 where 0 is the angle shown. Give an exact value, not a decimal approximation.

bogdanovich [222]

Answer:

cos(∅) = 3/5

Step-by-step explanation:

cos(∅) = adjacent/hypotenuse

We don't know what the hypotenuse is so we gotta use Pythagorean theorem to find it.

a² + b² = c²

4² + 3² = c²

√(4² + 3²) = c

c = 5 , this is our hypotenus

cos(∅) = adjacent/hypotenuse

cos(∅) = 3/5

8 0

3 years ago

Read 2 more answers

Consider each expression. Is the value of the expression negative?

tatyana61 [14]

Answer:

A.

No

B.

Yes

C.

Yes

Step-by-step explanation:

7 0

3 years ago