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JulijaS [17]
3 years ago
13

Tony, Martin, and Alfredo play together on a basketball team. During practice one day, they each shot 20 free throws. Tony made

14 out of 20, Alfredo made 3/4 of his shots, and Martin made 60% of his shots. Who should the coach choose to shoot free throws during the game? Explain.
Mathematics
1 answer:
Vanyuwa [196]3 years ago
7 0

Answer:

Alfredo

Step-by-step explanation:

He should choose Alfredo because he shot the highest percentage of 75% or 15 of 20 shots that he made. Whereas Tony only made 14 out of 20 which is 65% and Martin only made 60% or 13 out of 20, so as a coach you want to choose your best shooter.

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Sergeeva-Olga [200]

The cost of the sheets is less for the second example, the second example is the better deal.

Consider the first example:

Here, A brand of sheets is on sale for “Buy one get one at 50% off”. If each sheet costs $18.00.

So, the value of the first sheet will be $18,

And since the other sheet is at 50% off .

That is it will be half of the original value

= 50/100 * 18

=9

Therefore, the cost of two sheets

=$18 + $9

= $27.

So, Six sheets will cost

=$27+$27+$27

= $81

Cost of six sheets will be $81

Now, consider the second example

In the second example sheets are 30% off.

So, 30% of 18

= $6.

Subtract that value from 18 and you will get $12.

So, cost of one sheet =  $12.

cost of 6 sheet

=  $12×6

= $72  

In the first example, Six sheets costs $81, while in the second example six sheets cost $72.

Since the cost is less for the second example. So, the second example is the better deal.

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2 years ago
Drag each function to the correct location on the table. Not all labels will be used.
nevsk [136]
The next one is 4th degree, so z to the fourth
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3 years ago
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Which statement best illustrates using the vertical line test to determine if the graph below is a function of x ?
kirill115 [55]

If something is a function, every x-value, only has one (1) y-value. If the line x = 0 intersects the graph in two points, there are to values for y (instead of one). Therefore the graph is not a function of x.


Your answer is A.


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3 years ago
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The frequency distributions of two data sets are shown in the dot plots below.
fredd [130]

Answer:

1st, 4th and 6th statements are true.

Step-by-step explanation:

We have been given two dot-plots and we are asked to select all the true statements about given dot plots.

Let us write all the data points of both dot plots.

Data set 1:  

1, 1, 1, 1, 1, 2, 2, 2, 2, 2, 2, 2, 2, 3, 3, 3, 4, 4, 7.

Data set 2:  

1, 1, 1, 1, 1, 2, 2, 2, 2, 2, 2, 2, 2, 3, 3, 3, 4, 4.

1. The mean of data set 1 is greater than the mean of data set 2.

Let us find mean of both data sets.

\text{Mean of data set 1}=\frac{1+1+1+1+1+2+2+2+2+2+2+2+2+3+3+3+4+4+7}{19}

\text{Mean of data set 1}=\frac{45}{19}

\text{Mean of data set 1}=2.3684\approx 2.37  

\text{Mean of data set 2}=\frac{1+1+1+1+1+2+2+2+2+2+2+2+2+3+3+3+4+4}{18}

\text{Mean of data set 2}=\frac{38}{18}

\text{Mean of data set 2}=2.11

We can see that mean of data set 1 is greater than mean of data set 2, therefore, 1st statement is true.

2. The mean of data set 1 is equal to the mean of data set 2.

Since mean of data set 1 is greater than mean of data set 2, therefore, 2nd statement is false.

3. The median of data set 1 is greater than the median of data set 2.

Since data set 1 has 19 data points, so median of data set 1 will be value of 10th data set, that is 2.

Our data set 2 has 18 data points, so median of data set 2 will be the average of 9th and 10th data points.

\text{Median of data set 2}=\frac{2+2}{2}

\text{Median of data set 2}=\frac{4}{2}=2

Since median of data set 2 is also 2, therefore, 3rd statement is not true.

4. The median of data set 1 is equal to the median of data set 2.

Since both data set's median is 2, therefore, 4th statement is true.

5. The standard deviation of data set 1 is smaller than the standard deviation of data set 2.

Using online SD calculator we get SD of data set 1 is 1.422 and SD of data set 2 is 0.936. Since 1.422 is greater than 0.936, therefore, 5th statement is false.

6. The data sets have the same interquartile range.


Q_1\text{ of data set 1}=1

Q_3\text{ of data set 1}=3

\text{IQR of data set 1}=3-1=2

Q_1\text{ of data set 2}=1

Q_3\text{ of data set 2}=3

\text{IQR of data set 2}=3-1=2

Since both data set's IQR is 2, therefore, 6th statement is true.

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