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3 years ago

Which conditional statement has a false converse?

Mathematics

1 answer:

exis [7]3 years ago

8 0

Consider the converses:

a) If two planes have no points in common, then they are parallel. (true)

b) If a point lies on the y-axis, then it has x-coordinate 0. (true)

c) If two angles have the same measure, then they are congruent. (true)

d) If a figure has four sides, then it is a square. (FALSE) (A figure with 4 sides may not even be a plane figure.)

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Nooooooooooooooooooooooo

Natasha_Volkova [10]

Answer: yes

Step-by-step explanation:

Simply just yes

7 0

3 years ago

Please help!!

weqwewe [10]

Answer:

The vertex of the parabola = (-7 , -4)

Step-by-step explanation:

Step(i):-

Given that the parabola y = 4 x² + 56 x +192

y = 4 (x² + 14 x + 48 )

y = 4 ( x² + 2 × 7 (x) + 49-1)

y = 4 ( x² + 2 × 7 (x) + 49)- 4

we apply the formula

(a +b)² = a² + 2ab + b²

y = 4 ( x + 7 )² - 4

Step(ii):-

The general form of the parabola in algebraically

y = a ( x-h)² +k

The equation

y = 4 ( x + 7 )² - 4

y = 4 ( x-(-7))² - 4

The vertex of the parabola (h,k) = (-7 , -4)

Final answer:-

The vertex of the parabola = (-7 , -4)

8 0

3 years ago

What is the difference? StartFraction 2 x + 5 Over x squared minus 3 x EndFraction minus StartFraction 3 x + 5 Over x cubed minu

Sunny_sXe [5.5K]

Answer:

First option is the correct option.

Step-by-step explanation:

$\frac{2x + 5}{ {x}^{2} - 3x } - \frac{3x + 5}{ {x}^{3} - 9x } - \frac{x + 1}{ {x}^{2} - 9 }$

Factor out X from the expression

$\frac{2x + 5}{x(x - 3)} - \frac{3x + 5}{x( {x}^{2} - 9)} - \frac{x + 1}{ {x}^{2} - 9}$

Using ${a}^{2} - {b}^{2} = (a - b)(a + b)$ , factor the expression

$\frac{2x + 5}{x(x - 3)} - \frac{3x + 5}{x(x - 3)(x + 3) } - \frac{x + 1}{(x - 3)(x + 3)}$

Write all numerators above the Least Common Denominators x ( x - 3 ) ( x + 3 )

$\frac{(x + 3) \times (2x - 5) - (3x + 5) - x \times (x + 1)}{x(x - 3)(x + 3)}$

Multiply the parentheses

$\frac{2 {x}^{2} + 5x + 6x + 15 - (3x + 5) - x(x + 1)}{x(x - 3)(x + 3)}$

When there is a (-) in front of an expression in parentheses, change the sign of each term in the expression

$\frac{2 {x}^{2} + 5x + 6x + 15 - 3x - 5 - x \times (x + 1)}{x(x - 3)(x + 3)}$

Distribute -x through the parentheses

$\frac{2 {x}^{2} + 5x + 6x + 15 - 3x - 5 - {x}^{2} - x }{x(x - 3)(x + 3)}$

Using ${a}^{2} - {b}^{2} = (a + b)(a - b)$ , simplify the product

$\frac{2 {x}^{2} + 5x + 6x + 15 - 3x - 5 - {x}^{2} - x}{x( {x}^{2} - 9)}$

Collect like terms

$\frac{ {x}^{2} + 7x + 15 - 5}{x( {x}^{2} - 9)}$

Subtract the numbers

$\frac{ {x}^{2} + 7x + 10}{ x({x}^{2} - 9)}$

Distribute x through the parentheses

$\frac{ {x}^{2} + 7x + 10}{ {x}^{3} - 9x}$

Write 7x as a sum

$\frac{ {x}^{2} + 5x +2x + 10 }{ {x}^{3} - 9x }$

Factor out X from the expression

$\frac{x(x + 5) + 2x + 10}{ {x}^{3} - 9x}$

Factor out 2 from the expression

$\frac{x( x + 5) + 2(x + 5)}{ {x}^{3} - 9x }$

Factor out x + 5 from the expression

$\frac{(x + 5)(x + 2)}{ {x}^{3} - 9x }$

Hope this helps...

Best regards!!

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