A circle has a circumference of 18. It has an arc length of 6.

Mathematics

2 answers:

ra1l [238]3 years ago

7 0

The central angles of the arc is 120 degrees

IRINA_888 [86]3 years ago

3 0

Answer:

120

Step-by-step explanation:

my brother helped me

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Thomas wrote the equation y equals 3x + 3/4 when Sandra her equation they discovered that her equation had all the same Solution

Mice21 [21]

Were options given to you?

6 0

3 years ago

Y=6-x In this case, what would be the slope and y-intercept? I'm having a hard time trying to get it to the y=mx+b format.

frutty [35]

Answer:

Slope = $\frac{-1}{1}$ or -1

y = 6

Step-by-step explanation:

The equation given (y = 6 - x) is the same as saying

y = -1x + 6

Since we have a negative x variable and a positive 6 and would also be graphed the same. The only difference is that the second equation I just mentioned resembles the y = mx + b expression more. In this case the slope would be

Slope = $\frac{-1}{1}$ or -1

While the y-intercept would be

y = 6 - x

y = 6 - 0

y = 6

4 0

2 years ago

Given that (in picture)...

GuDViN [60]

<h3>Answer: a = -3 and b = 5</h3>

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Work Shown:

Multiply top and bottom by $\sqrt{2}$ to rationalize the denominator

$\frac{10-\sqrt{18}}{\sqrt{2}}\\\\\frac{\sqrt{2}(10-\sqrt{18})}{\sqrt{2}*\sqrt{2}}\\\\\frac{\sqrt{2}*10-\sqrt{2}*\sqrt{18}}{\sqrt{2*2}}\\\\\frac{\sqrt{2}*10-\sqrt{2*18}}{\sqrt{4}}\\\\\frac{10\sqrt{2}-\sqrt{36}}{2}\\\\\frac{10\sqrt{2}-6}{2}\\\\\frac{-6+10\sqrt{2}}{2}\\\\\frac{2(-3+5\sqrt{2})}{2}\\\\-3+5\sqrt{2}\\\\$