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3 years ago

Perform the indicated operation.

Mathematics

1 answer:

Evgen [1.6K]3 years ago

3 0

Answer:

-2

a^2+5a+6

Step-by-step explanation:

this is the answer

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I need some help with my homework so may someone help me not in a rush just need this done

Paladinen [302]

Answer:

-25

Step-by-step explanation:

First he bought 3 tires which total costed 105, then returned 2, so he got $70 back, meaning he had $35. Then he found 2 $20 bills, which raised his total to $75. Then, he bought a phone for $90, so he has -25 dollars left

6 0

3 years ago

A sandwich store charges a delivery fee to bring lunch to an office building. One office pays $33 for 4 turkey sandwiches. Anoth

shutvik [7]

Answer:

$12

Step-by-step explanation:

assuming that the cost of delivery is constant irrespective of the number ordered

Let the cost of sandwich be x

First office

$33=4x+c where c is the cost of delivery

Second office

$61=8x+c

These two are simultaneous equation. Subtracting the equation of first office from the second office we obtain

4x=28

Therefore, x=28/4=7

The cost of delivery is 33-(4*7)=33-28=5

Therefore, one sandwich plus delivery costs 7+5=$12

5 0

3 years ago

1.00 is 5% of what number

spin [16.1K]

Answer:

Step-by-step explanation:

If you work this out you get 1:

5/100*20

5 divided by 100 is 0.05 then 0.05 times 20 is 1

5 0

3 years ago

The perimeter of a rectangle is 30 inches. It’s area is 44 square inches. Find its length and width.

Verizon [17]

Answer:

length 11 width 4

Step-by-step explanation:

perimeter:

11+11=22

4+4=8

22+8=30

area:

11*4=44

4 0

2 years ago

LORAN is a long range hyperbolic navigation system. Suppose two LORAN transmitters are located at the coordinates (−60,0) and (6

USPshnik [31]

LORAN follows an hyperbolic path.

The equation of the hyperbola is: $\mathbf{\frac{x^2}{2500} + \frac{y^2}{1100} = 1}$

The coordinates are given as:

$\mathbf{(x,y) = (-60,0)\ (60,0)}$

The center of the hyperbola is

$\mathbf{(h,k) = (0,0)}$

The distance from the center to the focal points is given as:

$\mathbf{c = 60}$

Square both sides

$\mathbf{c^2 = 3600}$

The distance from the receiver to the transmitters is given as:

$\mathbf{2a = 100}$

Divide both sides by 2

$\mathbf{a = 50}$

Square both sides

$\mathbf{a^2 = 2500}$

We have:

$\mathbf{b^2 = c^2 - a^2}$

This gives

$\mathbf{b^2 = 3600 - 2500}$

$\mathbf{b^2 = 1100}$

The equation of an hyperbola is:

$\mathbf{\frac{(x - h)^2}{a^2} + \frac{(y - k)^2}{b^2} = 1}$

So, we have:

$\mathbf{\frac{(x - 0)^2}{2500} + \frac{(y - 0)^2}{1100} = 1}$

$\mathbf{\frac{x^2}{2500} + \frac{y^2}{1100} = 1}$

Hence, the equation of the hyperbola is: $\mathbf{\frac{x^2}{2500} + \frac{y^2}{1100} = 1}$