Since the two equations equal y, set them equal to each other.
x-1=-2x+5
From there, solve for x.
First get x on one side, by using the addition property of equality.
x-1=-2x+5
3x-1=5
Isolate x by adding 1.
3x=6
Lastly get x all by itself by dividing each side by 3.
x=2
You can now substitute your x-value, 2, into one of the equations (or both, if you wish; either one will result in the same answer.)
y=x-1
y=2-1
y=1
OR
y=-2x+5
y=-2(2)+5
y=-4+5
y=1
Final answer:
x=2 and y=1
Any questions or anything you would like me to clarify, feel free to ask :)
To find the product of <span>-2x^3+x-5 and x^3-3x-4, we need to multiply each term in the first polynomial by the second polynomial. (So, x^3 - 3x - 4) times ....
-2x^3 = -2x^6 + 6x^4 + 8x^3
x = x^4 - 3x^2 - 4x
-5 = -5x^3 + 15x + 20
If we add all these together, we get (-2x^6 + 7x^4 + 3x^3 - 3x^2 + 11x + 20)</span>
The decimals ordered from least to greatest are as followed:
Least: 2.009
2.09
2.19
2.9
Greatest: 2.901
I hope I have helped in some way, shape or form!
Given:
Consider the given expression is

To find:
The radical form of given expression.
Solution:
We have,



![[\because x^{\frac{1}{n}}=\sqrt[n]{x}]](https://tex.z-dn.net/?f=%5B%5Cbecause%20x%5E%7B%5Cfrac%7B1%7D%7Bn%7D%7D%3D%5Csqrt%5Bn%5D%7Bx%7D%5D)
![[\because x^{\frac{1}{n}}=\sqrt[n]{x}]](https://tex.z-dn.net/?f=%5B%5Cbecause%20x%5E%7B%5Cfrac%7B1%7D%7Bn%7D%7D%3D%5Csqrt%5Bn%5D%7Bx%7D%5D)
Therefore, the required radical form is
.