Left at 12 p.m.
traveled 3 hrs and 5 min.....now it is 3:05 p.m.
stopped for fuel, 10 minutes....now it is 3:15 p.m.
drove for 1 hr and 20 min.....now its 4:35 p.m
Answer:
Step-by-step explanation:
First confirm that x = 1 is one of the zeros.
f(1) = 2(1)^3 - 14(1)^2 + 38(1) - 26
f(1) = 2 - 14 + 38 - 26
f(1) = -12 + 38 = + 26
f(1) = 26 - 26
f(1) = 0
=========================
next perform a long division
x -1 || 2x^3 - 14x^2 + 38x - 26 || 2x^2 - 12x + 26
2x^3 - 2x^2
===========
-12x^2 + 28x
-12x^2 +12x
==========
26x -26
26x - 26
========
0
Now you can factor 2x^2 - 12x + 26
2(x^2 - 6x + 13)
The discriminate of the quadratic is negative. (36 - 4*1*13) = - 16
So you are going to get a complex result.
x = -(-6) +/- sqrt(-16)
=============
2
x = 3 +/- 2i
f(x) = 2*(x - 1)*(x - 3 + 2i)*(x - 3 - 2i)
The zeros are
1
3 +/- 2i
Answer:
hello thereeeee
ans is 23.5
Step-by-step explanation:
so lets start
first of all remove decimal of divisor 1.1/25.85 multiplying by 10
11/258.5
now first multiply by 2
now we get 22 and subtract with 25 => 25-22 = 3
so left is
38
now 11*3 = 33
so now by 3
38-33= 5
bringing another 5 down
we get 55
now quotient is 23. something ( as we bought .5 down)
and now 11*5 = 55
so
23.5 is answer
