Write the ratios for sin A and cos A. Not drawn to scale sinA= 24/10, cosA = 10/26 sinA= 24/26, cosA = 10/24

Mathematics

1 answer:

vagabundo [1.1K]1 year ago

8 0

To find the values of trigonometric functions, we can use the acronym SOHCAHTOA, which stands for:

$\begin{gathered} \sin\theta=\frac{opposite}{hypotenue} \\ \\ \cos\theta=\frac{adjacent}{hypotenuse} \\ \\ \tan\theta=\frac{opposite}{adjacent} \end{gathered}$

Because we are only looking for sin A and cos A, we'll use SOH and CAH. Remember that the positions are relative to angle A. So side BC would be the opposite and side AC would be the adjacent sides.

$\begin{gathered} \sin A=\frac{24}{26}\text{ }or\text{ }\frac{12}{13} \\ \\ cosA=\frac{10}{26}\text{ }or\text{ }\frac{5}{13} \end{gathered}$

The answer is the third option, sin A = 24/26, cos A = 10/26.

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If sin θ = 1 over 4 and tan θ > 0, what is the value of cos θ? (1 point)

Dima020 [189]

Answer:

There are two options: b) $\frac{\sqrt{15}}{4}$ , c) $\sqrt{15}$ .

Step-by-step explanation:

By Trigonometry, we know that function tangent is equal to the following identity in terms of functions sine and cosine:

$\tan \theta = \frac{\sin \theta}{\cos \theta}$ (1)

If we know that $\tan \theta > 0$ and $\sin \theta = \frac{1}{4}$ , then $\cos \theta > 0$ . Hence, we have two possibilities: b) $\frac{\sqrt{15}}{4}$ , c) $\sqrt{15}$ .