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charle [14.2K]
3 years ago
9

PLZZZ HELP will mark brainleist

Mathematics
1 answer:
Mashcka [7]3 years ago
8 0
The answer would be 25.12 circumstance equals 2(3.14)r so the inner circle would be 2(3.14)2=12.56 and the whole circle would equal 2(3.14)6=37.68. You subtract 37.68-12.56=25.12
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If a triangular pyramid has a base area of 10ft and a height of 6ft, what is the volume?
arlik [135]

Answer: 20 ft³

Step-by-step explanation:

volume of triangular pyramid = \frac{1}{3} bh

  • b = base area = 10 ft
  • h = height = 6 ft

Therefore, the volume is:

\frac{1}{3} *10*6=\frac{1}{3}*60=\frac{60}{3}=20

4 0
3 years ago
First.
velikii [3]

Answer:o

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
The perimeter of a rhombus is 180 cm and one of its diagonals is 72 cm. Find the length of the other diagonal and area of the rh
rewona [7]

Hi there! :)

<u>Answer:</u>

Length of the second diagonal: 54 cm

Area of the rhombus: 1,944 cm²


Step-by-step explanation:

1) To find the value of the second diagonal, you first need to know some important properties of rhombuses:

Since the perimeter is 180, and by definition a rhombus has four congruent sides (of equal length), each side length of the rhombus is equal to 45.

The diagonals of rhombuses also form four right triangles, with hypotenuses equal to the side length of the rhombus and legs equal to half the lengths of the diagonals. In this case one hypotenuse would be equal to 45 and one leg would be equal to 36 (72 ÷ 2 = 36).

We can therefore use the Pythagorean Theorem to solve for one-half of the unknown diagonal:

c² = a² + b² → Where "c" is the hypotenus & "a" and "b" are the two other sides.

<u>45² = 36² + b²</u> → Where "b" is the half of the unknown diagonal.

We can now solve this equation for "b":

<u>45²</u> = <u>36²</u> + b²

45² = <u>2,025</u>

36² = <u>1,296</u>

2,025 = <u>1,296</u> + b²

Subtract "1,296" from each side of the equation → 2,025 - 1,296 = <u>729</u>

729 = b<u>²</u>

Square root on each side of the equation → √729 = <u>27</u>

<u>27 = b</u>

Since "b" represents half of the unknown diagonal, we need to multiply by 2 to find the full length of the diagonal:

27 × 2 = <u>54 ⇒ Length of the other diagonal.</u>


2) To find the area of the rhombus, you need to multiply the length of the 2 diagonals and divide the answer by 2:

<u>(72 × 54)</u> ÷ 2 = A

Multiply "72" & "54" together → 72 × 54 = <u>3,888</u>

<u>3,888 ÷ 2</u> = A

<u>1,944 = A</u>


There you go! I really hope this helped, if there's anything just let me know! :)

3 0
3 years ago
Suppose that an object whose is 10th weighs 50 N find the weight of an object whose is 6 kg
Nady [450]
Weight is another term for the force from mass multiplied by acceleration due to gravity, the equation being expressed as f = ma, being force, mass, and acceleration respectively.

We already have 2 parts of the equation,50 = 10a 

Acceleration due to gravity on the planet is 5 m/s^2

Plug it into the equation f = ma

f=6kg x 5m/s^2

Weight or force from gravity is 60N.

8 0
3 years ago
Is this equation a linear function? If so give the intersepts 12x+3y=6
Katarina [22]
Dear Mendozaaj55, 12x + 3y = 6 is a linear function. To find the y-intercept set x = 0 and solve --> 3y = 6 --> y = 2. Therefore, the y-intercept is (0,2). To find the x-intercept, set y = 0 and solve. 12x = 6 ---> x = .5---> the x-intercept is the coordinate (.5, 0). Best.
7 0
3 years ago
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