Question

Simplify: (3y)^4 (times) y^-2 A) 1/2y^2 B) 3y^2 C) 1/81 y^2 D) 81 y^2

Answer 1

$(3y)^{4} * y^{-2}$

$((3y)(3y)(3y)(3y)) * \frac{1}{y^{2}}$

$81y^{4} * \frac{1}{y^{2}}$

$81y^{2}$

D. 81y²

Answer 2

$(3y)^4\cdot y^{-2}=81y^4\cdot y^{-2}=81y^{2}$