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3 years ago

Determine the value of cot 36º.

Mathematics

1 answer:

elixir [45]3 years ago

4 0

Answer:

Step-by-step explanation:

Use a table with trigonometric functions (look at the photo) or use the calculator knowing that:

$\cot\theta=\dfrac{1}{\tan\theta}=\left(\tan\theta\right)^{-1}$

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The height of a wave in California varies directly with the seconds that pass by. At 4 seconds, the wave is 6 feet high. Find th

Mrrafil [7]

Answer:

k=3/2

Step-by-step explanation:

6=k(4) where k is constant, or

k=6/4 which is equal to k=3/2

7 0

3 years ago

PLS HELP ME....

dalvyx [7]

Answer:

I believe it's A) 5x + 6y = 58 8x + 11y = 97

Step-by-step explanation:

Reason is, adult tickets and child tickets are two different things, so they require two different variables, and two different equations because they have two different sums. (This was probably already obvious to you though).

Hope this helps :)

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8 0

3 years ago

What is the volume of this prism?

Fiesta28 [93]

Answer:

36 cubic inches

Step-by-step explanation:

v=(3)(6)(2)=36

Hope this helps

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3 years ago

Belinda used an online broker who charged a flat fee of $8.99 per transaction. If Belinda bought 100 shares of of BMN Inc, stock

lana66690 [7]

The total cost of transactions for Belinda is $899.

<u>Solution:</u>

Given that, Belinda used an online broker who charged a flat fee of $8.99 per transaction.

Belinda bought 100 shares of of BMN Inc, stock at \$12.85 a share,

We have to find what was the total cost of the transaction?

Now, we know that, transaction cost per transaction = $8.99

And, number of transactions = 100 shares.

Then, total cost of transaction = cost per transaction x number of transactions = 100 x 8.99 = $899

Hence, the total cost of transactions is $899

4 0

4 years ago

If f(x) = 4 – x2 and g(x) = 6x, which expression is equivalent to (g – f)(3)?

Oduvanchick [21]

Remember that $(g-f)(x)$ is $g(x)-f(x)$ . We know form our problem that $f(x)=4-x^2$ and $g(x)=6x$ , so:
$(g-f)(x)=g(x)-f(x)$
$(g-f)(x)=6x-(4-x^2)$
$(g-f)(x)=6x-4+x^2$

Now, to find $(g-f)(3)$ , we just need to evaluate $(g-f)(x)$ at 3. In other words, we are going to replace $x$ with 3:
$(g-f)(x)=6x-4+x^2$
$(g-f)(x)=6(3)-4+(3)^2$

We can conclude that the correct answer is <span>C.6(3) – 4 + 3^2 </span>

5 0

3 years ago