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3 years ago

How do i solve this in the quadratic formula?

Mathematics

1 answer:

liraira [26]3 years ago

6 0

Firstly mines 2x for 2 side
And combine 1 for 2 side
Result 6x^2+17x+5
So
(3x+1)(2x+5)=0
X=-1/3 or x=-5/2

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Find the perimeter of quadrilateral PQRS with the vertices P(2,4), Q(2,3), R(-2,-2), and S(-2,3).

storchak [24]

Answer:

$P=16.53\ units$

Step-by-step explanation:

we know that

The perimeter of quadrilateral PQRS is equal to the sum of its four length sides

the formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

we have

the vertices P(2,4), Q(2,3), R(-2,-2), and S(-2,3)

step 1

Find the distance PQ

P(2,4), Q(2,3)

substitute in the formula

$d=\sqrt{(3-4)^{2}+(2-2)^{2}}$

$d=\sqrt{(-1)^{2}+(0)^{2}}$

$d=\sqrt{1}$

$dPQ=1\ unit$

step 2

Find the distance QR

Q(2,3), R(-2,-2)

substitute in the formula

$d=\sqrt{(-2-3)^{2}+(-2-2)^{2}}$

$d=\sqrt{(-5)^{2}+(-4)^{2}}$

$dQR=\sqrt{41}\ units$

step 3

Find the distance RS

R(-2,-2), and S(-2,3)

substitute in the formula

$d=\sqrt{(3+2)^{2}+(-2+2)^{2}}$

$d=\sqrt{(5)^{2}+(0)^{2}}$

$dRS=5\ units$

step 4

Find the distance PS

P(2,4), S(-2,3)

substitute in the formula

$d=\sqrt{(3-4)^{2}+(-2-2)^{2}}$

$d=\sqrt{(-1)^{2}+(-4)^{2}}$

$dPS=\sqrt{17}\ units$

step 5

Find the perimeter

$P=PQ+QR+RS+PS$

substitute the values

$P=1+\sqrt{41}+5+\sqrt{17}$

$P=6+\sqrt{41}+\sqrt{17}$

$P=16.53\ units$

5 0

3 years ago

Need help like right now.

denpristay [2]

Let's go:

Big triangle:

12 + 3x - 6 = 3x + 6

10 + 8 = 18

$\frac{10}{18} = \frac{3x - 6}{3x + 6} \\\\ 10.(3x + 6) = 18.(3x - 6) \\\ 30x + 60 = 54x - 108 \\\ 54x - 30x = 60 + 108 \\\ 24x = 168 \\\ x = 7$

I hope I helped you.

4 0

4 years ago

Read 2 more answers

I need help ASAP PLEASEEEEEEEEEEEEEEEEEE

Oksanka [162]

Answer:

97,99,101,103

Step-by-step explanation:

Let x = first odd integer

x+2 = 2nd odd integer

x+4 = 3rd odd integer

x+6 = 4th odd integer

Sum of 4 odd integers is 400

x+ (x+2) + (x+4)+(x+6) = 400

Combine like terms

4x +12 = 400

Subtract 12 from each side

4x+12-12 = 400-12

4x = 388

Divide by 4 on each side

4x/4 = 388/4

x=97

The first integer is 97

The 2nd is 97+2 =99

The third ix 97+4 = 101

The 4th is 97+6 = 103

5 0

3 years ago

Read 2 more answers

Mary owned n sheep and Sam had exactly 4 times as many sheep as Mary.

Veseljchak [2.6K]

Answer:

The least value of n is, 9.

Step-by-step explanation:

Mary(M) owned the number of sheep is n i.e, M = n sheep

Sam(S) had exactly four times as many sheep as Mary , i.e, S = 4 n sheep

As per the given condition Mary buys 17 extra sheep

Now, Mary has total number of sheep, M = n +17 sheep

And Sam sells 8 of his sheep that means he has now,

But, Sam still has more sheep than Mary i.e,

Solve an inequality:

Add 8 both sides we get;

Simplify:

Now, subtract n from both the side, we get;

Simplify:

Since n is the number of sheep in integer,

then the least value of n is, 9.

8 0

3 years ago

Read 2 more answers

What is the estimate difference 422-284

Akimi4 [234]

If you're rounding to the nearest 100th the total would be 100. 422 would round to 300 and 284 would be rounded to 300 which equals 100.

7 0

3 years ago