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solong [7]
4 years ago
3

the length of the rectangle is 3 ft less than double the width, the area of the rectangle is 44 ft squared. what is the length a

nd the width?

Mathematics
2 answers:
hammer [34]4 years ago
8 0
A=wl is the area of the rectangle but here’s a picture to show u this might help u with the length and width have a wonderful and nice day

aliya0001 [1]4 years ago
6 0
We need to find the length, l, and the width, w. Let's set up the two equations with the information found in the question:

l = 2w - 3
w = w
A = 44ft^{2}

We know that area is equal to length * width (A=l*w), so let's substitute those values

A=l*w
A=(2w-3)*w
A=2 w^{2}-3w

And we know that the area is equal to 44 ft^{2}:

44=2 w^{2}-3w

Now we set equal to 0 and factor in order to get w:

0=2 w^{2}-3w-44
0=(2w-11)(w+4)

Then we set each factor equal to zero and solve for w. We get the two values:

\frac{11}{2} and -4 for w.

We know that the width cannot be negative, so we take the value that is positive, \frac{11}{2}

So now we know that w = \frac{11}{2}, so we plug in this value into the equation for the length:

l=2w-3
l=2( \frac{11}{2})-3
l= \frac{22}{2}-3
l=11-3=8 

So we now know that the length is 8, and the width is \frac{11}{2}.
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