Question

the length of the rectangle is 3 ft less than double the width, the area of the rectangle is 44 ft squared. what is the length and the width?

Answer 1

A=wl is the area of the rectangle but here’s a picture to show u this might help u with the length and width have a wonderful and nice day

Answer 2

We need to find the length, l, and the width, w. Let's set up the two equations with the information found in the question:

l = 2w - 3
w = w
A = 44$ft^{2}$

We know that area is equal to length * width ($A=l*w$), so let's substitute those values

$A=l*w$
$A=(2w-3)*w$
$A=2 w^{2}-3w$

And we know that the area is equal to $44 ft^{2}$:

$44=2 w^{2}-3w$

Now we set equal to 0 and factor in order to get w:

$0=2 w^{2}-3w-44$
$0=(2w-11)(w+4)$

Then we set each factor equal to zero and solve for w. We get the two values:

$\frac{11}{2}$ and $-4$ for w.

We know that the width cannot be negative, so we take the value that is positive, $\frac{11}{2}$

So now we know that w = $\frac{11}{2}$, so we plug in this value into the equation for the length:

$l=2w-3$
$l=2( \frac{11}{2})-3$
$l= \frac{22}{2}-3$
$l=11-3=8$ 

So we now know that the length is 8, and the width is $\frac{11}{2}$.