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Tju [1.3M]
2 years ago
9

Please help me asap! I will give brainly!

Mathematics
2 answers:
myrzilka [38]2 years ago
4 0

Answer:

Step-by-step explanation:

The ratio of contestants to winners is 4 : 1 so to find the number of winners you must divide by 4, so you must divide 120 by 4, which is 30.

MariettaO [177]2 years ago
3 0

Answer:

Divide the number of contestants by 4 and when there is 120 contestants there is 30 winners

Step-by-step explanation:

Looking back at past sequences we can see that when we had 8 contestants we had 2 winners 8/4=2 and we also saw 16/4=4 so that was the formula now we just had to do it on 120 contestants and now we get 30 winners....Hope this helps! :)

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A+5=5a+5 how do i do this problem
Natali5045456 [20]

Answer:

0 = a

Step-by-step explanation:

The first thing to do is subtract 5 from both sides.

a + 5 = 5a + 5

   - 5          - 5      

The 5's cancel out.

Now we have a + 0 = 5a

You next subtract the a from both sides.

a + 0 = 5a

-a          -a

0 = 4a

Lastly would to get a by itself so then we divide 4 from both sides

0 = 4a

_     _  

4     4

0 = a

5 0
2 years ago
I need help with these questions
Fofino [41]

Answer:

Rule up a graph sheet and text it to me so I can help

6 0
3 years ago
Giving brainlist to whoever answers plz
Elanso [62]

Answer:

Okay! It should be the 3 one.

-2(3)+30=24

Step-by-step explanation:

5 0
2 years ago
Read 2 more answers
fancy goldfish x cost $3 each and common goldfish y cost $1 Graph tje function y=20-3x determine how many of each type of goldfi
NemiM [27]
6 Fancy, and 20 Common
4 0
3 years ago
Help answer and EXPLAIN STEP BY STEP
pychu [463]

15. (-k^{3} -5k^{2} + 1) - (6k^{3}-k^{2} -2)

Step 1: Distribute the subtraction sign to all the numbers in the second set of parentheses...

(-k^{3} -5k^{2} + 1) - (6k^{3}-k^{2} -2)

-k^{3} -5k^{2} +1 - 6k^{3} +k^{2} +2

Step 2: Combine like terms (k^{2}'s go with k^{2}'s)

-k^{3} -5k^{2} + 1 - 6k^{3}+k^{2} +2

-5k^{2} +k^{2}

-4k^{2}

-k^{3} -4k^{2} + 1 - 6k^{3}+2

Step 3: Combine like terms (k^{3}'s go with k^{3}'s)

-k^{3} -4k^{2} + 1 - 6k^{3}+2

-k^{3} + (- 6k^{3})

-7k^{3}

-7k^{3} -4k^{2} + 1 +2

Step 4: Combine like terms (normal numbers go with normal numbers)

-7k^{3} -4k^{2} + 1 +2

1 + 2

3

-7k^{3} -4k^{2} + 3

You were correct!

16. 49m^2 - 84mn + 36n^2

I don't really know how to explain this one but I got: (7m-6n)(7m-6n)

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3 years ago
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