Answer:
total 66$
Step-by-step explanation:
let price of bro s be x and pencil be y
according to Qn
at 1 cond
3x+4=30____(1)
2x+5y=27____(2)
solve botth and get value of each bros and pencil and then at last add,30$,27$,6$,3$
Answer:
We conclude that the calibration point is set too high.
Step-by-step explanation:
We are given the following in the question:
Population mean, μ = 1000 grams
Sample mean,
= 1001.1 grams
Sample size, n = 50
Alpha, α = 0.05
Population standard deviation, σ = 2.8 grams
First, we design the null and the alternate hypothesis
![H_{0}: \mu = 1000\text{ grams}\\H_A: \mu > 1000\text{ grams}](https://tex.z-dn.net/?f=H_%7B0%7D%3A%20%5Cmu%20%3D%201000%5Ctext%7B%20grams%7D%5C%5CH_A%3A%20%5Cmu%20%3E%201000%5Ctext%7B%20grams%7D)
We use One-tailed(right) z test to perform this hypothesis.
Formula:
![z_{stat} = \displaystyle\frac{\bar{x} - \mu}{\frac{\sigma}{\sqrt{n}} }](https://tex.z-dn.net/?f=z_%7Bstat%7D%20%3D%20%5Cdisplaystyle%5Cfrac%7B%5Cbar%7Bx%7D%20-%20%5Cmu%7D%7B%5Cfrac%7B%5Csigma%7D%7B%5Csqrt%7Bn%7D%7D%20%7D)
Putting all the values, we have
![z_{stat} = \displaystyle\frac{ 1001.1 - 1000}{\frac{2.8}{\sqrt{50}} } = 2.778](https://tex.z-dn.net/?f=z_%7Bstat%7D%20%3D%20%5Cdisplaystyle%5Cfrac%7B%201001.1%20-%201000%7D%7B%5Cfrac%7B2.8%7D%7B%5Csqrt%7B50%7D%7D%20%7D%20%3D%202.778)
Now, ![z_{critical} \text{ at 0.01 level of significance } = 2.326](https://tex.z-dn.net/?f=z_%7Bcritical%7D%20%5Ctext%7B%20at%200.01%20level%20of%20significance%20%7D%20%3D%202.326)
Since,
![z_{stat} > z_{critical}](https://tex.z-dn.net/?f=z_%7Bstat%7D%20%3E%20z_%7Bcritical%7D)
We reject the null hypothesis and accept the alternate hypothesis. We accept the alternate hypothesis. We conclude that the calibration point is set too high.
Answer:
(0.0316) U (0.0631)
Step-by-step explanation:
C on edge
7 / 2 1/3 = 7/1 / 7/3 = 7/1 * 3/7 = 21/7 = 3 ( enough flour for 3 batches of muffins)
1 1/2 * 3 = 4 1/2 cups of brown sugar needed
Answer:
The volume of the sphere is 14m³
Step-by-step explanation:
Given
Volume of the cylinder = ![21m^3](https://tex.z-dn.net/?f=21m%5E3)
Required
Volume of the sphere
Given that the volume of the cylinder is 21, the first step is to solve for the radius of the cylinder;
<em>Using the volume formula of a cylinder</em>
The formula goes thus
![V = \pi r^2h](https://tex.z-dn.net/?f=V%20%3D%20%5Cpi%20r%5E2h)
Substitute 21 for V; this gives
![21 = \pi r^2h](https://tex.z-dn.net/?f=21%20%3D%20%5Cpi%20r%5E2h)
Divide both sides by h
![\frac{21}{h} = \frac{\pi r^2h}{h}](https://tex.z-dn.net/?f=%5Cfrac%7B21%7D%7Bh%7D%20%3D%20%5Cfrac%7B%5Cpi%20r%5E2h%7D%7Bh%7D)
![\frac{21}{h} = \pi r^2](https://tex.z-dn.net/?f=%5Cfrac%7B21%7D%7Bh%7D%20%3D%20%5Cpi%20r%5E2)
The next step is to solve for the volume of the sphere using the following formula;
![V = \frac{4}{3}\pi r^3](https://tex.z-dn.net/?f=V%20%3D%20%5Cfrac%7B4%7D%7B3%7D%5Cpi%20r%5E3)
Divide both sides by r
![\frac{V}{r} = \frac{4}{3r}\pi r^3](https://tex.z-dn.net/?f=%5Cfrac%7BV%7D%7Br%7D%20%3D%20%5Cfrac%7B4%7D%7B3r%7D%5Cpi%20r%5E3)
Expand Expression
![\frac{V}{r} = \frac{4}{3}\pi r^2](https://tex.z-dn.net/?f=%5Cfrac%7BV%7D%7Br%7D%20%3D%20%5Cfrac%7B4%7D%7B3%7D%5Cpi%20r%5E2)
Substitute ![\frac{21}{h} = \pi r^2](https://tex.z-dn.net/?f=%5Cfrac%7B21%7D%7Bh%7D%20%3D%20%5Cpi%20r%5E2)
![\frac{V}{r} = \frac{4}{3} * \frac{21}{h}](https://tex.z-dn.net/?f=%5Cfrac%7BV%7D%7Br%7D%20%3D%20%5Cfrac%7B4%7D%7B3%7D%20%2A%20%5Cfrac%7B21%7D%7Bh%7D)
![\frac{V}{r} = \frac{84}{3h}](https://tex.z-dn.net/?f=%5Cfrac%7BV%7D%7Br%7D%20%3D%20%5Cfrac%7B84%7D%7B3h%7D)
![\frac{V}{r} = \frac{28}{h}](https://tex.z-dn.net/?f=%5Cfrac%7BV%7D%7Br%7D%20%3D%20%5Cfrac%7B28%7D%7Bh%7D)
Multiply both sided by r
![r * \frac{V}{r} = \frac{28}{h} * r](https://tex.z-dn.net/?f=r%20%2A%20%5Cfrac%7BV%7D%7Br%7D%20%3D%20%5Cfrac%7B28%7D%7Bh%7D%20%2A%20r)
------ equation 1
From the question, we were given that the height of the cylinder and the sphere have equal value;
This implies that the height of the cylinder equals the diameter of the sphere. In other words
, where D represents diameter of the sphere
Recall that ![D = 2r](https://tex.z-dn.net/?f=D%20%3D%202r)
So, ![h = D = 2r](https://tex.z-dn.net/?f=h%20%3D%20D%20%3D%202r)
![h = 2r](https://tex.z-dn.net/?f=h%20%3D%202r)
Substitute 2r for h in equation 1
![V = \frac{28r}{2r}](https://tex.z-dn.net/?f=V%20%3D%20%5Cfrac%7B28r%7D%7B2r%7D)
![V = \frac{28}{2}](https://tex.z-dn.net/?f=V%20%3D%20%5Cfrac%7B28%7D%7B2%7D)
![V = 14](https://tex.z-dn.net/?f=V%20%3D%2014)
Hence, the volume of the sphere is 14m³