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victus00 [196]
3 years ago
7

Which inequality correctly compares One-third, Five-sixths, and Three-fifths? One-third < Three-fifths < Five-sixths One-t

hird < Five-sixths < Three-fifths Five-sixths < One-third < Three-fifths Five-sixths < Three-fifths < One-third
Mathematics
1 answer:
lilavasa [31]3 years ago
5 0

Answer:

\frac{1}{3}   \: <  \:  \frac{3}{5}   \: <  \:  \frac{5}{6}

Step-by-step explanation:

We want to compare the fractions

\frac{1}{3}, \frac{5}{6} , \frac{3}{5}

First, we collect LCM

The LCM of 3,6, and 5 is 30

\frac{1}{3} =  \frac{10}{30} ,  \\  \frac{5}{6} =  \frac{25}{30} , \\   \frac{3}{5}  = \frac{18}{30}

\frac{10}{30} , \frac{18}{30} ,  \frac{25}{30}

This means that

\frac{1}{3} , \frac{3}{5} ,  \frac{5}{6}

Hence,

\frac{1}{3}   \: <  \:  \frac{3}{5}   \: <  \:  \frac{5}{6}

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40.51x+12.45y=666.64
irga5000 [103]

Answer:

The graph of the equation 40.51x+12.45y=666.64 is attached with the answer where the horizontal axis represents the X axis and the vertical axis represents Y axis.

To plot the graph physically just find two points lying on the line. Mark the points on the graph sheet and then join them. This will give you the line represented by the equation.

To find points on the line assume the value of any one variable, substitute it in the equation, then solve the equation to find the value of other variable. For example : assume y = 1; substitute the value of y in the equation;

⇒ 40.51x + 12.45×1 = 666.64

⇒ 40.51x = 666.64 - 12.45

⇒ 40.51x = 654.19

⇒ x = \frac{654.19}{40.51}

⇒ x ≈ 16.149

Therefore point ( 16.149 , 1 ) lie on the graph of the equation.

***Only two points are required to plot this graph just because it represents a straight line, that we can conclude just by observing the equation. If in an equation the power of x is 1 or 0 and power of y is 1 or 0 then only it will represent a straight line in 2-D plane.***

5 0
3 years ago
Given:• PQRS is a rectangle.• mZ1 = 50°Р21SRWhat is mZ2?130°85°70°65°
Over [174]

To answer this question, we need to recall that: "the diagonals of a rectangle bisect each other"

Thus, if we assign the point of intersection of the two diagonals in the rectangle as point O, we can say that the triangle OQR is an "isosceles triangle". Note that this is because the lengths OR and OQ are equal since we know that: "the diagonals of a rectangle bisect each other". See the below diagram for clarity.

Now, we have to recall that:

- the base angles of any isosceles triangle are equal. This is a fact, and this means that the angles

- also the sum of all the angles in any triangle is 180 degrees

Now, considering the isosceles triangle OQR, we have that:

\angle OQR+\angle ORQ+\angle ROQ=180^o

Now, since the figure already shows that angle m\angle2+\angle ORQ+50^o=180^oNow, since we have established that the base angles m\angle2+m\angle2+50^o=180^owe can now solve the above equation for m<2 as follows:

\begin{gathered} m\angle2+m\angle2+50^o=180^o \\ \Rightarrow2m\angle2+50^o=180^o \\ \Rightarrow2m\angle2=180^o-50^o \\ \Rightarrow2m\angle2=130^o \\ \Rightarrow m\angle2=\frac{130^o}{2}=65^o \end{gathered}

Therefore, the correct answer is: option D

7 0
1 year ago
Help quick Given f(x) and g(x) = k⋅f(x), use the graph to determine the value of k.
Salsk061 [2.6K]

Answer:

k = -3

Step-by-step explanation:

F(x) has a positive slope

g(x) has a negative slope

Let x = -3

The y value goes from 1 to -3

g(x) = k⋅f(x)

-3 = k(1)

-3 = k

6 0
3 years ago
Guys please help! In triangle CDE, the measure of angle C is 90 degrees, side CD is 15 and DE is 3 more than CE. Find the length
AURORKA [14]
You can calculate it using the law of cosines: c^2=a^2+b^2-2*a*b*cos(C)

your triangle is
CD=15=a
CE=?=b
DE=CE+3=b+3=c
and C=90°

-> insert those values, with c substituted with b+3 to remove c

c^2=a^2+b^2-2*a*b*cos(C)
(b+3)^2=15^2+b^2-2*15*b*cos(90)
cos(90)=0->
(b+3)^2=15^2+b^2
b^2+2*3*b+3^2=225+b^2
6b+9=225
6b=216
b=36=CE

DE=CE+3=36+3=39
4 0
4 years ago
Please Help. I’m confused. I will give Brainliest Answer.
RUDIKE [14]

Answer:

A

Step-by-step explanation:

The other situations do not represent a 60% probability.

B is a situation in which 40% of people prefer aisle seats.

C is a situation in which 33% of people prefer aisle seats

D is a situation in which 66% of people prefer aisle seats.

3 0
3 years ago
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