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denis-greek [22]
3 years ago
13

a cage at a pet store has 9 white mice. in how many different ways can Dana choose 3 white mice to buy

Mathematics
1 answer:
hodyreva [135]3 years ago
3 0
In 39 different ways
Dana would choose 39
 white balls 
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This is due at 8:00PM please someone help
krek1111 [17]
10. A 11. D 12. A (wasn’t too sure about question 12)
6 0
3 years ago
The Graph describes the water level of creek after a rainstorm which best describes the domain in context?
belka [17]

The domain of a function are its possible input values

The domain of the function is <em>(b) all real numbers greater than or equal to 0.</em>

From the graph, we have the following observations

  • <em>t represents time (it is plotted on the x-axis)</em>
  • <em>t starts at 0</em>
  • <em>t has no end</em>

The above observations imply that; the domain starts from 0

Hence, the domain of the function is the set of all real numbers greater than or equal to 0.

Read more about domain at:

brainly.com/question/2709928

5 0
2 years ago
What is the correct evaluation of 3x2 + 4x - 2y2 + 4y + 5, when x is equal to -1 and y is equal to 5?
Julli [10]
3x2+4(-1)-2(5)2 +4(5)+5=
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6+-4-10+25
_________
31-14=17
8 0
3 years ago
A parallel system functions whenever at least one of its components works. Consider a parallel system of 5 components, and suppo
Aneli [31]

Answer:

Probability that component 4 works given that the system is functioning = 0.434 .

Step-by-step explanation:

We are given that a parallel system functions whenever at least one of its components works.

There are parallel system of 5 components and each component works independently with probability 0.4 .

Let <em>A = Probability of component 4 working properly, P(A) = 0.4 .</em>

<em>Also let S = Probability that system is functioning for whole 5 components, P(S)</em>

Now, the conditional probability that component 4 works given that the system is functioning is given by P(A/S) ;

P(A/S) =  {Means P(component 4 working and system also working)

divided by P(system is functioning)}

  P(A/S) =  {In numerator it is P(component 4 working) and in

                denominator it is P(system working) = 1 - P(system is not working)}

Since we know that P(system not working) means that none of the components is working in system and it is given with the probability of 0.6 and since there are total of 5 components so P(system working) = 1 - 0.6^{5} .

 Hence, P(A/S) = \frac{0.4}{1 - 0.6^{5} } = 0.434.    

7 0
3 years ago
The lifetime of LCD TV sets follows an exponential distribution with a mean of 100,000 hours. Compute the probability a televisi
kondaur [170]

Answer:

0.9

0.3012

0.1809

230258.5

Step-by-step explanation:

Given that:

μ = 100,000

λ = 1/μ = 1 / 100000 = 0.00001

a. Fails in less than 10,000 hours.

P(X < 10,000) = 1 - e^-λx

x = 10,000

P(X < 10,000) = 1 - e^-(0.00001 * 10000)

= 1 - e^-0.1

= 1 - 0.1

= 0.9

b. Lasts more than 120,000 hours.

X more than 120000

P(X > 120,000) = e^-λx

P(X > 120,000) = e^-(0.00001 * 120000)

P(X > 120,000) = e^-1.2

= 0.3011942 = 0.3012

c. Fails between 60,000 and 100,000 hours of use.

P(X < 60000) = 1 - e^-λx

x = 60000

P(X < 60,000) = 1 - e^-(0.00001 * 60000)

= 1 - e-^-0.6

= 1 - 0.5488116

= 0.4511883

P(X < 100000) = 1 - e^-λx

x = 100000

P(X < 60,000) = 1 - e^-(0.00001 * 100000)

= 1 - e^-1

= 1 - 0.3678794

= 0.6321205

Hence,

0.6321205 - 0.4511883 = 0.1809322

d. Find the 90th percentile. So 10 percent of the TV sets last more than what length of time?

P(x > x) = 10% = 0.1

P(x > x) = e^-λx

0.1 = e^-0.00001 * x

Take the In

−2.302585 = - 0.00001x

2.302585 / 0.00001

= 230258.5

3 0
3 years ago
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